19

I was wondering if it is possible to write a very simple game in TikZ; e.g. (very simple) Super Mario Bros. Here is Mario:

\documentclass[border=5pt,tikz]{standalone}
\begin{document}
    \begin{tikzpicture}
        \draw[step=.5cm] (0,0) grid (8,8);
        \foreach \x in {2.5,3,...,4.5}
        {
            \fill[red] (\x,7.5) rectangle +(.5,.5);
        }
        \foreach \x in {2,2.5,...,6}
        {
            \fill[red] (\x,7) rectangle +(.5,.5);
        }
        \foreach \x in {2,2.5,3}
        {
            \fill[brown!70!black] (\x,6.5) rectangle +(.5,.5);
        }
        \foreach \x in {3.5,4}
        {
            \fill[yellow!50!orange] (\x,6.5) rectangle +(.5,.5);
        }
        \fill[black] (4.5,6.5) rectangle +(.5,.5);
        \fill[yellow!50!orange] (5,6.5) rectangle +(.5,.5);
            \fill[brown!70!black] (1.5,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (2,6) rectangle +(.5,.5);
            \fill[brown!70!black] (2.5,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (3,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (3.5,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (4,6) rectangle +(.5,.5);
                \fill[black] (4.5,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (5,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (5.5,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (6,6) rectangle +(.5,.5);
        \begin{scope}[shift={(0,-.5)}]
            \fill[brown!70!black] (1.5,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (2,6) rectangle +(.5,.5);
            \fill[brown!70!black] (2.5,6) rectangle +(.5,.5);
            \fill[brown!70!black] (3,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (3.5,6) rectangle +(.5,.5);
            \fill[yellow!50!orange] (4,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (4.5,6) rectangle +(.5,.5);
                \fill[black] (5,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (5.5,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (6,6) rectangle +(.5,.5);
                \fill[yellow!50!orange] (6.5,6) rectangle +(.5,.5);
        \end{scope}
        \fill[brown!70!black] (2,5) rectangle +(.5,.5);
        \foreach \x in {2.5,3,...,4}
        {
            \fill[yellow!50!orange] (\x,5) rectangle +(.5,.5);
        }
        \foreach \x in {4.5,5,...,6}
        {
            \fill[black] (\x,5) rectangle +(.5,.5);
        }
        \foreach \x in {2.5,3,...,5}
        {
            \fill[yellow!50!orange] (\x,4.5) rectangle +(.5,.5);
        }
        \foreach \x in {2,2.5,...,5.5}
        {
            \fill[red] (\x,4) rectangle +(.5,.5);
        }
        \fill[blue] (3,4) rectangle +(.5,.5);
        \fill[blue] (4.5,4) rectangle +(.5,.5);
        \begin{scope}[shift={(0,-.5)}]
            \foreach \x in {1.5,2,...,6}
            {
                \fill[red] (\x,4) rectangle +(.5,.5);
            }
            \fill[blue] (3,4) rectangle +(.5,.5);
            \fill[blue] (4.5,4) rectangle +(.5,.5);
        \end{scope}
        \begin{scope}[shift={(0,-1)}]
            \foreach \x in {1,1.5,2,...,6.5}
            {
                \fill[red] (\x,4) rectangle +(.5,.5);
            }
            \fill[blue] (3,4) rectangle +(.5,.5);
                \fill[blue] (3.5,4) rectangle +(.5,.5);
                \fill[blue] (4,4) rectangle +(.5,.5);
            \fill[blue] (4.5,4) rectangle +(.5,.5);
        \end{scope}
        \fill[yellow!50!orange] (1,2.5) rectangle +(.5,.5);
        \fill[yellow!50!orange] (1.5,2.5) rectangle +(.5,.5);
            \fill[red] (2,2.5) rectangle +(.5,.5);
            \fill[blue] (2.5,2.5) rectangle +(.5,.5);
                \fill[yellow!50!orange] (3,2.5) rectangle +(.5,.5);
            \fill[blue] (3.5,2.5) rectangle +(.5,.5);
            \fill[blue] (4,2.5) rectangle +(.5,.5);
                \fill[yellow!50!orange] (4.5,2.5) rectangle +(.5,.5);
            \fill[blue] (5,2.5) rectangle +(.5,.5);
            \fill[red] (5.5,2.5) rectangle +(.5,.5);
                \fill[yellow!50!orange] (6,2.5) rectangle +(.5,.5);
                \fill[yellow!50!orange] (6.5,2.5) rectangle +(.5,.5);
        \foreach \x in {1,1.5,2}
        {
            \fill[yellow!50!orange] (\x,2) rectangle +(.5,.5);
        }
        \foreach \x in {2.5,3,...,5}
        {
            \fill[blue] (\x,2) rectangle +(.5,.5);
        }
        \fill[yellow!50!orange] (5.5,2) rectangle +(.5,.5);
        \fill[yellow!50!orange] (6,2) rectangle +(.5,.5);
        \fill[yellow!50!orange] (6.5,2) rectangle +(.5,.5);
        \begin{scope}[shift={(0,-1)}]
            \fill[yellow!50!orange] (1,2.5) rectangle +(.5,.5);
            \fill[yellow!50!orange] (1.5,2.5) rectangle +(.5,.5);
                \fill[blue] (2,2.5) rectangle +(.5,.5);
                \fill[blue] (2.5,2.5) rectangle +(.5,.5);
                    \fill[blue] (3,2.5) rectangle +(.5,.5);
                \fill[blue] (3.5,2.5) rectangle +(.5,.5);
                \fill[blue] (4,2.5) rectangle +(.5,.5);
                    \fill[blue] (4.5,2.5) rectangle +(.5,.5);
                \fill[blue] (5,2.5) rectangle +(.5,.5);
                \fill[blue] (5.5,2.5) rectangle +(.5,.5);
                    \fill[yellow!50!orange] (6,2.5) rectangle +(.5,.5);
                    \fill[yellow!50!orange] (6.5,2.5) rectangle +(.5,.5);
        \end{scope}
            \foreach \x in {2,2.5,3}
            {
                \fill[blue] (\x,1) rectangle +(.5,.5);
            }
        \begin{scope}[shift={(2.5,0)}]
            \foreach \x in {2,2.5,3}
            {
                \fill[blue] (\x,1) rectangle +(.5,.5);
            }
        \end{scope}
        \foreach \x in {1.5,2,2.5}
        {
            \fill[brown!70!black] (\x,.5) rectangle +(.5,.5);
        }
        \begin{scope}[shift={(3.5,0)}]
            \foreach \x in {1.5,2,2.5}
            {
                \fill[brown!70!black] (\x,.5) rectangle +(.5,.5);
            }
        \end{scope}
        \begin{scope}[shift={(0,-.5)}]
            \foreach \x in {1,1.5,2,2.5}
            {
                \fill[brown!70!black] (\x,.5) rectangle +(.5,.5);
            }
            \begin{scope}[shift={(4,0)}]
                \foreach \x in {1,1.5,2,2.5}
                {
                    \fill[brown!70!black] (\x,.5) rectangle +(.5,.5);
                }
            \end{scope}
        \end{scope}
    \end{tikzpicture}
\end{document}

Here is the output:

Screenshot

And here is the original:

Screenshot

Because you can create simple animations and controls in TikZ (see the Rubiks thread), it is maybe possible to generate a world (e.g. from Mario) , which is refreshed by some buttons.

For the beginn the pong game would be absolutely enough I think, because it is really hard to implement such things especially in TikZ.

As the title says, it would sound great if something like that would exist, so my question is: Does anybody have an idea how to do that? This is not a do-it-for-me – question, rather collecting ideas.

Improve this question
9
  • LaTeX will always produce pdf files I think. So if you want to produce a game, you'd have to create pdfs for all possible outcomes beforehand. Not sure if that would be fun. (+1 for the Mario ;-)
    – user121799
    Aug 6, 2018 at 23:44
  • @marmot: Yes, that's right, but I thought just like an interactive-animation-thing, you know? And thank you! ;)
    – current_user
    Aug 6, 2018 at 23:45
  • 3
    Interesting idea. Pkg animate, however, might not be the right tool here, as it does not allow branching. But PDF Layers (OCGs) could be an option (#pixels x #colours), to be enabled/hidden by JavaScript, possibly using random numbers, and/or by buttons.
    – AlexG
    Aug 7, 2018 at 7:00
  • 1
    @naphaneal Well, technically I agree but your probably know what I wanted to say, don't you? Even more explicitly: LaTeX will create a static document.
    – user121799
    Aug 7, 2018 at 13:58
  • 1
    A non-trivial game could be a puzzle: reorder previously shuffled cells to show Mario again by moving sub-rows and sub-columns towards a whole (Sliding Puzzle).
    – AlexG
    Aug 7, 2018 at 14:08

2 Answers 2

Reset to default
21

Sliding Puzzle

(Acrobat Reader required; pdflatex or lualatex)

This is a non-trivial game with user interaction, based on PDF Layers (OCGs, package ocgx2).

The picture is split into 15 tiles, stacked upon each other for every cell of the puzzle board, each on an individual PDF Layer. The total number of PDF Layers is thus 4 x 4 x 15 = 240. Their visibility is controlled by JavaScript, triggered by clicking on an array of transparent buttons overlaid on top of the puzzle board.

enter image description here

\documentclass[tikz,margin=1mm]{standalone}

\usepackage{xsavebox}
\usepackage[tikz]{ocgx2}
\usepackage{media9} % \mediabutton

\usepackage{tikzmarmots}
\usepackage{xcolor}\pagecolor{gray}
\usepackage{multido}
\usepackage{ifluatex}
\ifluatex\def\pdfpageattr{\pdfvariable pageattr}\fi

\begin{xlrbox}{Marmot}
  \begin{tikzpicture}[xscale=-1,transform shape]
    \useasboundingbox (0,0) rectangle (4.4,4.4);
    \node at (current bounding box.center) {\tikz\marmot[scale=2.1];};
  \end{tikzpicture}
\end{xlrbox}

%generating tiles Marmot.1, ..., Marmot.15
\multido{\nX=0.0+1.1,\iI=0+1}{4}{
  \multido{\nY=3.3+-1.1,\iJ=0+1}{4}{
    \ifnum\numexpr\iI+\iJ\relax>0
      \begin{xlrbox}{Marmot.\the\numexpr\iI+\iJ*4\relax}
        \begin{tikzpicture}
          \useasboundingbox (\nX,\nY) rectangle ++(1.1,1.1);
          \clip (\nX,\nY) rectangle ++(1.1,1.1);
          \node[inner sep=0pt, outer sep=0pt, anchor=south west,fill=white] at (0,0) {\theMarmot};
        \end{tikzpicture}
      \end{xlrbox}
    \fi
  }
}

\newcommand\MyStatus[2]{\ifnum#1=#2 visible\else invisible\fi}

%initialisations (JavaScript) on page-open (/O <<...>>)
\begingroup
\edef\x{\endgroup
  \pdfpageattr{
    \the\pdfpageattr
    /AA << /O << /S/JavaScript /JS (%
      var tile=new Array(4);
      var oldTile=new Array(4);
      for(var i=0;i<4;i++){
        tile[i]=new Array(4);
        oldTile[i]=new Array(4);
        for(var j=0;j<4;j++){
          tile[i][j]=new Array(15);
          oldTile[i][j]=i+j*4-1;
        }
      }
      ocg=this.getOCGs(this.pageNum);
      for(var i in ocg){
        ocgName=ocg[i].name.split('.');
        tile[ocgName[0]][ocgName[1]][ocgName[2]-1]=ocg[i];
      }%
      var swap_i=0; var swap_j=0;
      var onButtonClick=function(i,j){
        if(swap_i==i && swap_j!=j){
          for(var jj=swap_j; jj!=j; swap_j<j ? jj++ : jj--){
            if(jj!=swap_j) tile[i][jj][oldTile[i][jj]].state=false;
            newTile=oldTile[i][swap_j<j ? jj+1 : jj-1];
            oldTile[i][jj]=newTile;
            tile[i][jj][newTile].state=true;
          }
        } else if(swap_j==j && swap_i!=i){
          for(var ii=swap_i; ii!=i; swap_i<i ? ii++ : ii--){
            if(ii!=swap_i) tile[ii][j][oldTile[ii][j]].state=false;
            newTile=oldTile[swap_i<i ? ii+1 : ii-1][j];
            oldTile[ii][j]=newTile;
            tile[ii][j][newTile].state=true;
          }
        }
        if(swap_i==i || swap_j==j){
          if(oldTile[i][j]>-1)
            tile[i][j][oldTile[i][j]].state=false;
          oldTile[i][j]=-1;
          swap_i=i; swap_j=j;
        }
      };
    ) >> >>
  }
}
\x

\begin{document}

\begin{tikzpicture}
  \multido{\nX=0.0+1.1,\iI=0+1}{4}{%
    \multido{\nY=3.3+-1.1,\iJ=0+1}{4}{%
      %tiles
      \multido{\iK=1+1}{15}{%
        \begin{scope}[ocg={ref=\iI.\iJ.\iK,status=\MyStatus{\the\numexpr\iI+\iJ*4\relax}{\iK}}]%
          \node[inner sep=0pt, outer sep=0pt, anchor=south west] at (\nX,\nY) {\xusebox{Marmot.\iK}};
        \end{scope}
      }
      %button array
      \draw[
        line width=0,
        postaction={
          path picture={
            \path (path picture bounding box.south west) coordinate (p1)
              (path picture bounding box.north east) coordinate (p2)
              (p1) node[inner sep=0pt,anchor=south west,outer sep=0pt] {%
                \mediabutton[jsaction={try{onButtonClick(\iI,\iJ);}catch(e){}}]{%
                  \tikz \useasboundingbox (p1) rectangle (p2);%
                }%
              };
          }
        }
      ] (\nX,\nY) rectangle ++(1.1,1.1);
    }
  }
\end{tikzpicture}

\end{document}

Original Answer

For this kind of games based on a pixel array using a given set of pre-defined colours, the TikZ-part is straightforward to be implemented; making use of package ocgx2, we simply put each pixel colour on an individual PDF Layer.

The whole logic of the game can then be implemented in JavaScript. It programmatically controls the visibility of each pixel colour.

As a trivial example, we implement a "game" whose sole purpose is to shuffle the pixel colours by pressing a button and to enjoy the result (Acrobat Reader or Foxit required for viewing):

enter image description here

\documentclass[tikz,margin=1mm]{standalone}
\usepackage[tikz]{ocgx2}
\usepackage{media9} % \mediabutton

\newcommand{\mycolour}[1]{\ifcase#1
white%0
\or
black%1
\or
red%2
\or
orange%3
\or
blue%4
\or
brown%5
\or
yellow%6
\fi}

\begin{document}

%set up canvas (16x16 pixels^2) x (7 colours)
\begin{tikzpicture}
  \foreach \X in {0,1,...,15} {
    \foreach \Y in {0,1,...,15} {
      \foreach \Z in {0,1,...,6} {
        \begin{scope}[ocg={ref=\X.\Y.\Z,status=invisible}]
          \node[minimum size=0.5cm,draw,fill=\mycolour{\Z}] at (\X/2,-\Y/2){};
        \end{scope}
      }
    }
  }
  \node at (3.75,-8) {%
    \mediabutton[
      jsaction={
        %initialisation
        if(typeof pixelcolour==='undefined'){
          var pixelcolour=new Array(16);
          var oldcolour=new Array(16);
          for(var i=0;i<16;i++){
            pixelcolour[i]=new Array(16);
            oldcolour[i]=new Array(16);
            for(var j=0;j<16;j++){
              pixelcolour[i][j]=new Array(7);
              oldcolour[i][j]=0;
            }
          }
          ocg=this.getOCGs(this.pageNum);
          for(i in ocg){
            ocgName=ocg[i].name.split('.');
            pixelcolour[ocgName[0]][ocgName[1]][ocgName[2]]=ocg[i];
          }  
        }
        %randomise colours
        for(i=0;i<16;i++){
          for(j=0;j<16;j++){
            newcolour=Math.floor(Math.random()*7);
            pixelcolour[i][j][oldcolour[i][j]].state=false;
            pixelcolour[i][j][newcolour].state=true;
            oldcolour[i][j]=newcolour;
          }
        }
      }
    ]{\fbox{Random}}
  };
\end{tikzpicture}
\end{document}
Improve this answer
14
  • 1
    Are you on a RaspberryPi :-)? Yes, it takes a while. 20 seconds on my PC.
    – AlexG
    Aug 7, 2018 at 11:33
  • 1
    Trying to upload a static PNG, but imgur rejects it for some reason.
    – AlexG
    Aug 7, 2018 at 11:48
  • 2
    @Sebastiano Pictures and a new game added :-).
    – AlexG
    Aug 10, 2018 at 9:21
  • 1
    @jvriesem That's easy. Look for the single \draw in the code and replace it with \path. Though I personally would keep the lines for this kind of game.
    – AlexG
    Oct 23, 2020 at 7:09
  • 1
    @AlexG: Update: the game made it through the final published version! It doesn't seem to have any visual glitches or performance issues now, so perhaps the PDF reader updated how it handles these things in the past year.
    – jvriesem
    Oct 23, 2021 at 17:40
11

Four steps with Super Mario.

\documentclass{article}
\usepackage{tikz}
\usepackage{animate}

\newcommand{\MarioStop}{
\fill[red] (2.5,8) -- (5,8) -- (5,7.5) -- (6.5,7.5) -- (6.5,7) -- (2,7) -- (2,7.5) -- (2.5,7.5);
\fill[brown!70!black] (2,7) -- (3.5,7) -- (3.5,6.5) -- (3,6.5) -- (3,6) -- (3.5,6) -- (3.5,5.5) -- (2.5,5.5) -- (2.5,6.5) -- (2,6.5);
\fill[brown!70!black] (4.5,7) -- (4.5,6) -- (5,6) -- (5,7);
\fill[brown!70!black](5,6) -- (5.5,6) -- (5.5,5.5) -- (6.5,5.5) -- (6.5,5) -- (4.5,5) -- (4.5,5.5) -- (5,5.5);
\fill[brown!70!black] (1.5,6.5) -- (2,6.5) -- (2,5.5) -- (2.5,5.5) -- (2.5,5) -- (1.5,5);
\fill[yellow!50!orange] (3.5,7) -- (4.5,7) -- (4.5,6) -- (5,6) -- (5,5.5) -- (4.5,5.5) -- (4.5,5) -- (6,5) -- (6,4.5) -- (2.5,4.5) -- (2.5,5.5) -- (3.5,5.5) -- (3.5,6) -- (3,6) -- (3,6.5) -- (3.5,6.5);
\fill[yellow!50!orange] (2,6.5) -- (2.5,6.5) -- (2.5,5.5) -- (2,5.5);
\fill[yellow!50!orange] (5,7) -- (5.5,7) -- (5.5,6.5) -- (6.5,6.5) -- (6.5,6) -- (7,6) -- (7,5.5) -- (5.5,5.5) -- (5.5,6) -- (5,6);
\fill[red] (2,4.5) -- (3,4.5) -- (3,3) -- (2.5,3) -- (2.5,2.5) -- (2,2.5) -- (2,3) -- (1,3) -- (1,3.5) -- (1.5,3.5) -- (1.5,4) -- (2,4);
\fill[red] (3.5,4.5) -- (5.5,4.5) -- (5.5,4) -- (6.5,4) -- (6.5,3.5) -- (7,3.5) -- (7,3) -- (6,3) -- (6,2.5) -- (5.5,2.5) -- (5.5,3) -- (5,3) -- (5,4) -- (4.5,4) -- (4.5,3.5) -- (3.5,3.5);
\fill[blue] (3,4.5) -- (3.5,4.5) -- (3.5,3.5) -- (4.5,3.5) -- (4.5,4) -- (5,4) -- (5,3) -- (5.5,3) -- (5.5,2) -- (6,2) -- (6,1) -- (4.5,1) -- (4.5,1.5) -- (3.5,1.5) -- (3.5,1) -- (2,1) -- (2,2) -- (2.5,2) -- (2.5,3) -- (3,3);
\fill[yellow!50!orange] (3,3) -- (3.5,3) -- (3.5,2.5) -- (3,2.5);
\fill[yellow!50!orange] (4.5,3) -- (5,3) -- (5,2.5) -- (4.5,2.5);
\fill[yellow!50!orange] (6,3) -- (7,3) -- (7,1.5) -- (6,1.5) -- (6,2) -- (5.5,2) -- (5.5,2.5) -- (6,2.5);
\fill[yellow!50!orange] (1,3) -- (2,3) -- (2,2.5) -- (2.5,2.5) -- (2.5,2) -- (2,2) -- (2,1.5) -- (1,1.5);
\fill[brown!70!black] (1.5,1) -- (3,1) -- (3,0) -- (1,0) -- (1,0.5) -- (1.5,0.5);
\fill[brown!70!black] (5,1) -- (6.5,1) -- (6.5,0.5) -- (7,0.5) -- (7,0) -- (5,0);
}
\newcommand{\MarioFStep}{
\fill[red] (3,7.5) -- (5.5,7.5) -- (5.5,7) -- (7,7) -- (7,6.5) -- (2.5,6.5) -- (2.5,7) -- (3,7);
\fill[brown!70!black] (2.5,6.5) -- (4,6.5) -- (4,6) -- (3.5,6) -- (3.5,5.5) -- (4,5.5) -- (4,5) -- (3,5) -- (3,6) -- (2.5,6);
\fill[brown!70!black] (2,6) -- (2.5,6) -- (2.5,5) -- (3,5) -- (3,4.5) -- (2,4.5);
\fill[brown!70!black] (5,6.5) -- (5,5.5) -- (5.5,5.5) -- (5.5,6.5);
\fill[brown!70!black] (5.5,5.5) -- (6,5.5) -- (6,5) -- (7,5) -- (7,4.5) -- (5,4.5) -- (5,5) -- (5.5,5);
\fill[brown!70!black] (1.5,2.5) -- (2.5,2.5) -- (2.5,2) -- (2,2) -- (2,1) -- (1.5,1) -- (1.5,0.5) -- (1,0.5) -- (1,1.5) -- (1.5,1.5);
\fill[brown!70!black] (3.5,1) -- (5,1) -- (5,0.5) -- (5.5,0.5) -- (5.5,0) -- (3.5,0);
\fill[yellow!50!orange]  (2.5,6) -- (3,6) -- (3,5) -- (2.5,5);
\fill[yellow!50!orange] (4,6.5) -- (5,6.5) -- (5,5.5) -- (5.5,5.5) -- (5.5,5) -- (5,5) -- (5,4.5) -- (6.5,4.5) -- (6.5,3.5) -- (7,3.5) -- (7,3) -- (6.5,3) -- (6.5,2.5) -- (5.5,2.5) -- (5.5,3.5) -- (6,3.5) -- (6,4) -- (3,4) -- (3,5) -- (4,5) -- (4,5.5) -- (3.5,5.5) -- (3.5,6) -- (4,6);
\fill[yellow!50!orange]  (5.5,6.5) -- (6,6.5) -- (6,6) -- (7,6) -- (7,5.5) -- (7.5,5.5) -- (7.5,5) -- (6,5) -- (6,5.5) -- (5.5,5.5);
\fill[yellow!50!orange] (2,3.5) -- (2.5,3.5) -- (2.5,2.5) -- (1.5,2.5) -- (1.5,3) -- (2,3);
\fill[red] (2.5,4) -- (4.5,4) -- (4.5,3.5) -- (5,3.5) -- (5,4) -- (5.5,4) -- (5.5,2.5) -- (3,2.5) -- (3,3) -- (2.5,3);
\fill[blue] (4.5,4) -- (4.5,3.5) -- (5,3.5) -- (5,4);
\fill[blue] (2.5,3) -- (3,3) -- (3,2.5) -- (6,2.5) -- (6,1.5) -- (5.5,1.5) -- (5.5,1) -- (4,1) -- (4,1.5) -- (3.5,1.5) -- (3.5,1) -- (2,1) -- (2,2) -- (2.5,2);
}
\newcommand{\MarioSStep}{
\fill[red] (3,8) -- (5.5,8) -- (5.5,7.5) -- (7,7.5) -- (7,7) -- (2.5,7) -- (2.5,7.5) -- (3,7.5);
\fill[red] (1.5,4.5) -- (3.5,4.5) -- (3.5,3) -- (2.5,3) -- (2.5,3.5) -- (1.5,3.5);
\fill[red] (4.5,4.5) -- (5.5,4.5) -- (5.5,4) -- (6.5,4) -- (6.5,3.5) -- (7,3.5) -- (7,3) -- (6,3) -- (6,3.5) -- (5,3.5) -- (5,4) -- (4.5,4);
\fill[brown!70!black] (2.5,7) -- (4,7) -- (4,6.5) -- (3.5,6.5) -- (3.5,6) -- (4,6) -- (4,5.5) -- (3,5.5) -- (3,6.5) -- (2.5,6.5);
\fill[brown!70!black]  (2,6.5) -- (2.5,6.5) -- (2.5,5.5) -- (3,5.5) -- (3,5) -- (2,5);
\fill[brown!70!black]  (5,7) -- (5,6) -- (5.5,6) -- (5.5,7);
\fill[brown!70!black]  (5.5,6) -- (6,6) -- (6,5.5) -- (7,5.5) -- (7,5) -- (5,5) -- (5,5.5) -- (5.5,5.5);
\fill[brown!70!black]  (1,1.5) -- (2,1.5) -- (2,1) -- (2.5,1) -- (2.5,0.5) -- (3,0.5) -- (3,0) -- (1.5,0) -- (1.5,0.5) -- (1,0.5);
\fill[brown!70!black]  (6.5,2.5) -- (7,2.5) -- (7,3) -- (7.5,3) -- (7.5,1) -- (6.5,1);
\fill[yellow!50!orange] (4,7) -- (5,7) -- (5,6) -- (5.5,6) -- (5.5,5.5) -- (5,5.5) -- (5,5) -- (6.5,5) -- (6.5,4.5) -- (3,4.5) -- (3,5.5) -- (4,5.5) -- (4,6) -- (3.5,6) -- (3.5,6.5) -- (4,6.5);
\fill[yellow!50!orange] (2.5,6.5) -- (3,6.5) -- (3,5.5) -- (2.5,5.5);
\fill[yellow!50!orange] (5.5,7) -- (6,7) -- (6,6.5) -- (7,6.5) -- (7,6) -- (7.5,6) -- (7.5,5.5) -- (6,5.5) -- (6,6) -- (5.5,6);
\fill[yellow!50!orange] (0.5,4) -- (1.5,4) -- (1.5,3.5) -- (2,3.5) -- (2,3) -- (1.5,3) -- (1.5,2.5) -- (0.5,2.5);
\fill[yellow!50!orange] (6.5,4) -- (8,4) -- (8,3) -- (7,3) -- (7,3.5) -- (6.5,3.5);
\fill[blue] (3.5,4.5) -- (4.5,4.5) -- (4.5,4) -- (5,4) -- (5,3.5) -- (6,3.5) -- (6,2.5) -- (6.5,2.5) -- (6.5,1) -- (5,1) -- (5,1.5) -- (3.5,1.5) -- (3.5,1) -- (2,1) -- (2,1.5) -- (1.5,1.5) -- (1.5,2) -- (2,2) -- (2,2.5) -- (2.5,2.5) -- (2.5,3) -- (3.5,3);
\fill[yellow!50!orange] (4,3.5) -- (4.5,3.5) -- (4.5,3) -- (4,3);
}
\begin{document}

\begin{animateinline}[autoplay,loop,
    begin={\begin{tikzpicture}},
    end={\end{tikzpicture}}]{2}
\MarioStop\newframe
\MarioFStep\newframe
\MarioSStep\newframe
\MarioFStep\newframe
\MarioSStep\newframe
\MarioFStep\newframe
\MarioSStep\newframe
\MarioFStep\newframe
\MarioSStep\newframe
\MarioStop
\end{animateinline}
\end{document}

Super Mario Four Steps

Improve this answer
5
  • 1
    Can you add a picture, please?
    – Sebastiano
    Aug 9, 2018 at 20:37
  • 1
    @Sebastiano It's an easy animation of Super Mario that make four steps.
    – vi pa
    Aug 9, 2018 at 20:40
  • 1
    It is very nice to see the animation. :-). However +1.
    – Sebastiano
    Aug 9, 2018 at 20:43
  • 1
    Someone knows how to get the translation when mario walk.
    – vi pa
    Aug 9, 2018 at 20:53
  • looks like a lot of work. +1.
    – Roland
    Dec 23, 2020 at 6:04

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