Here is a solution, if you don't need margin notes, with two variants for the second equation. A small remark: for multiline indices, you should use \substack
, not \stackrel
which is designed to add something over a relation symbol
, so that the two rows use the same font size. I also used smaller delimiters.
\documentclass{article}
\usepackage{geometry}
\usepackage{mathtools}
\begin{document}
\begin{multline}
\begin{aligned}
&\smashoperator{ \sumⁿ_{\substack{i=1\\(j,i) ∈ Q}}}\, \Biggl\{ w^{1}_{ijR}+\sum^{m=1}_{\substack{(m,i) ∈ Q\\m ≠ j}} \Biggl[ (w^{2}_{ijmR}+w^{2}_{ijm,R-1}) + \smashoperator{\sum^{l=1}_{\substack{(l,i) ∈ Q\\i ≠ j ≠ m}}} (w^{3}_{ijmlR}+w^{3}_{ijml,R-1}+w^{3}_{ijml,R-2}) \Biggr] \Biggr\} \\
+ & \smashoperator{\sumⁿ_{\substack{j=1\\(l,i) ∈ Q}}} \Biggl\{ w^{1}_{jiR}+ \sum^{m=1}_{\substack{(m,j) ∈ Q\\ m ≠ i}} \Biggl[ (w^{2}_{jimR}+w^{2}_{jmi,R-1}) + \smashoperator{\sum^{l=1}_{\substack{(l,j) ∈ Q\\ m ≠ i ≠ l}}}(w^{3}_{jimlR}+w^{3}_{jmil,R-1}+w^{3}_{jmli,R-2}) \Biggr] \Biggr\}
\end{aligned} \\
=1 ,\qquad i=1,...,n,\quad R=1,...,n-1
\end{multline}\\
\begin{multline} \smashoperator{\sum^{n}_{\substack{j=1\\ (j,i)\in Q}}} \Biggl\{w^{1}_{ijR}+w^{1}_{ij,R+1}+\smashoperator{\sum^{n}_{\substack{m=1 \\ (m,i)\in Q \\ m\neq j}}} \,\biggl[w^{2}_{ijm,R-1}+w^{2}_{ijmR}+w^{2}_{ijm,R+1} \\[-6ex]
+ \smashoperator{\sum^{n}_{\substack{l=1 \\ (l,i)\in Q \\ i\neq j\neq m}}}(w^{3}_{ijml,R-2}+w^{3}_{ijmlR}+w^{3}_{ijml,R+2}) \biggr] \Biggr\} \leq 1
\end{multline} \\
\begin{equation}
\begin{aligned}[b]
\smashoperator{\sum^{n}_{\substack{j=1\\ (j,i)\in Q}}} \Biggl\{w^{1}_{ijR}+w^{1}_{ij,R+1}+\smashoperator{\sum^{n}_{\substack{m=1 \\ (m,i)\in Q \\ m\neq j}}} \,\biggl[w^{2}_{ijm,R-1} & + w^{2}_{ijmR}+w^{2}_{ijm,R+1} \\[-5.5ex]
& + \smashoperator{\sum^{n}_{\substack{l=1 \\ (l,i)\in Q \\ i\neq j\neq m}}}(w^{3}_{ijml,R-2}+w^{3}_{ijmlR}+w^{3}_{ijml,R+2}) \biggr] \Biggr\} \leq 1
\end{aligned}
\end{equation}
\end{document}
