50

The way I currently do it is $x \not | y$, which looks awful. There's got to be something better available.

57

$x\nmid y$ saves the day.

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  • Thanks, Harald! For some reason I thought I had tried this already. – Qiaochu Yuan Oct 23 '10 at 22:40
  • 3
    Remember that \nmid is not defined in amsmath. amssymb is required for \nmid. – 4ae1e1 Nov 7 '13 at 20:14
61

An alternative to \nmid is to use the \centernot command from the centernot package. The resulting \centernot\mid symbol aligns perfectly with \mid and has a more pronounced slash than \nmid:

alt text

(On the right, the image shows how the commands behave in sub/superscript.)

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29

Another good looking (best to me) and easy option is to use the command \notdivides from the mathabx package. The code

\documentclass{article}
\usepackage{mathabx}
\begin{document}
\[ \prod_{a \notdivides b}^{a \notdivides b} a \notdivides b \]
\end{document}

creates the output

a \notdivides b

The negating line is longer than \nmid's but shorter than \centernot's.

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6

$x \mod{y} \neq 0$ ;)

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  • 7
    That's a programmer's answer. Mathematicians would probably write it $x \neq 0 (\mathrm{mod} y)$ – Phil Miller Oct 25 '10 at 2:53
  • 2
    We'd both be wrong in an algebraist's eyes because a congruence is technically in order: $x \ncong 0 \left( \mathrm{mod} y\right)$. Thanks for pointing that out. – everybodyelse Oct 25 '10 at 4:34
  • 9
    The TeXnically correct way to do either of those is $x \ncong 0 \pmod{y} :) – Ryan Reich Nov 21 '10 at 8:59
2

One possibility to assert, in symbols, that "a divides b" would be to use the MnSymbol package and then use $a \divides b$ (or $a \ndivides b$ for doesn't divide).

As I am typing a good deal of ring theory, I'm using those all the time.

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