pgfplotstable: How to get header-elements?

Question

How can I replace e.g. the 'zeros' by the cell content of the current header?

\documentclass[border=5pt]{standalone}
\usepackage{pgfplotstable}

\pgfplotstableread{
A   B
1   2
0   2
1   0
0   2
0   2
1   0
}\test

\begin{document}

\pgfplotstabletypeset[string type,
%string replace={0}{aaa}
]{\test}

\end{document}

Answer 1

Suggestion using expl3:

\documentclass[border=5pt]{standalone}
\usepackage{pgfplotstable}
\pgfplotsset{compat=newest}
\pgfplotstableread{
A   B
1   2
0   2
1   0
0   2
0   2
1   0
}\test
\pgfplotstablegetcolsof{\test}
\pgfmathtruncatemacro\colmax{\pgfplotsretval-1}

\usepackage{expl3}
\ExplSyntaxOn
\int_step_inline:nnnn
  {0}{1}{\colmax}
  {
    \pgfplotstablegetcolumnnamebyindex{#1}\of\test\to\colname
    \pgfplotstablemodifyeachcolumnelement{\colname}\of\test\as\cell
      {\pgfmathparse{\cell==0?"\colname":\cell}\xdef\cell{\pgfmathresult}}
  }
\ExplSyntaxOff

\begin{document}
\pgfplotstabletypeset[string type]{\test}
\end{document}

Answer 2

Possible:

\pgfplotsinvokeforeach{0,1} {%
\pgfplotstableset{
columns/#1/.style = {
string replace={0}{\pgfplotstablegetelem{0}{[index]#1}\of\test \pgfplotsretval}
}}}%

But this is not so nice, because I have to say \of\test, so this does not work as a general style...

\documentclass[border=5pt]{standalone}
\usepackage{pgfplotstable}

\pgfplotstableread[header=false]{
A   B
1   2
0   2
1   0
0   2
0   2
1   0
}\test

\begin{document}

% Nullen ersetzen
\pgfplotsinvokeforeach{0,1} {%
\pgfplotstableset{
columns/#1/.style = {
string replace={0}{\pgfplotstablegetelem{0}{[index]#1}\of\test \pgfplotsretval}
}}}%

\pgfplotstabletypeset[string type,
skip rows between index={0}{1},% Benennungszeile ausblenden
every head row/.style={output empty row},% keinen header anzeigen
]{\test}

%Test:  \pgfplotstablegetelem{0}{[index]0}\of\test \pgfplotsretval
%\pgfplotstablegetelem{0}{[index]1}\of\test \pgfplotsretval
\end{document}