enter image description here

A planner figure, any visual tools can help?

  • 5
    Well, general relativity is even harder for beginners, but this does not mean that others will do your computations for you. Likewise, if you have difficulties with drawing your picture, this does not mean that others take over. For newcomers we sometimes make exceptions, but after the first answer you have already an idea what an MWE is. So please show us what you've tried.
    – user121799
    Dec 15, 2018 at 2:46
  • 3
    @marmot i will try after class, thank you. if anyone have answer, comment after i have tried.
    – Ben
    Dec 15, 2018 at 3:40
  • 2
    Next time please don't upload images that are not upright. Seeing those is much harder than doing others. Dec 15, 2018 at 6:25
  • @ArtificialStupidity i see, it’s not upright, I will correct. thank you!
    – Ben
    Dec 15, 2018 at 7:40

2 Answers 2


considering your answer as starting point (as missing mwe in your question)...

with use of tikz librariesangles (for drawing angles), \arrows.meta (for nice arrows), calc (for drawing orthogonal vectors) and quotes (for angle labels), and use polar coordinates the code for your image can be as follows:

\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{angles, arrows.meta, calc, quotes}

    \begin{tikzpicture}[% styles used in image code
         > = Straight Barb, % defined in "arrows.meta
dot/.style = {circle, fill,
              minimum size=2mm, inner sep=0pt, outer sep=0pt,
              node contents={}},
box/.style = {draw, thin, minimum  width=2mm, minimum height=4mm,
              inner sep=0pt, outer sep=0pt,
              node contents={}, sloped},
my angle/.style args = {#1/#2}{draw,->,
                               angle radius=#1,
                               angle eccentricity=#2,
                               } % angle label position!
% coordinate axis
\draw[->] (-3,0) -- (6,0) node[below left] {$x$};
\draw[->] ( 0,0) coordinate[label=below:$O$] (O)
                 -- (0,6) node[below left] {$y$};
% axis units
\draw[->,thick] (0,0) -- (1,0) node[below] {$i$};
\draw[->,thick] (0,0) -- (0,1) node[right] {$j$};
% dashed line
\draw[dashed]  (-2,0) coordinate (s)
                      -- ++ (32:4.2) node (d1) [dot];
% angle theta, used "angles" and "quotes" library
\pic [draw, my angle=12mm/0.8, "$\Theta$"] {angle = O--s--d1};
% solid line
\draw[thick]    (d1)  -- node (m) [box] ++ (32:3) node (d2) [dot];
% angle N_z
\pic [draw, my angle=6mm/1.5, "$Nz$"] {angle = d2--m--d1};
% forces in y and x direction
\draw[->] (m.center) -- ++ (1,0) node[below] {$ F_xi $};
\draw[->] (m.center) -- ++ (0,2) node[left] {$ F_xj $};
% vectors v_1, v, v_2, used "calc" library
\draw[->] (d1) -- ($(d1)!12mm! 90:(d2)$);
\draw[->] (d1) -- ($(d1)!12mm!270:(d2)$) coordinate[label=below right:$v_1$] (v1);
\draw[->] (m.center) -- ($(m.center)!12mm!270:(d2)$) coordinate[label=below right:$v$] (v);
\draw[->] (d2) -- ($(d2)!12mm!270:(d1)$);
\draw[->] (d2) -- ($(d2)!12mm! 90:(d1)$) coordinate[label=below right:$v_2$] (v2);
% dashed line between vectors v_1, v_2
\draw [dashed] (v1)--(v2);

enter image description here

  • In the image attached to the question, v1, v and v2 are not of the same length.
    – AndréC
    Dec 16, 2018 at 4:29

Yeah, it is not difficult. when you meet problems, do not afraid, just do it step by step.

Although my method based on translation and rotation,\draw everything, not smart, the code is very redundant.

There is the first version. I will keep learning. next, I will use \coordinate to make code simple and efficient.

code as follows:

\draw[->] (-2.4,0)--(5,0) node[below] {$ x $}; %coordinate
\draw[->] (0,0)--(0,6) node[left] {$ y $};

\draw[->,thick] (0,0)--(1,0) node[near start,below] {$ O $} node[below] {$ i $}; %unit coordinate
\draw[->,thick] (0,0)--(0,1) node[left] {$ j $};

\draw [dashed,xshift=-2cm,rotate=32]  (0,0)--(4.2,0); %line 
\draw [xshift=-2cm,rotate=32]  (4.2,0)--(7.2,0); 
\draw[->] (-0.8cm,0) arc (0:32:1.2cm) node[left=1.2pt,below=2.1pt] {$ \Theta $}; %arc 1

\filldraw[fill=black,xshift=-2cm,rotate=32] (4.2,0) circle (0.1cm); % M1
\draw[->,xshift=-2cm,rotate=32] (4.2,0)--(4.2,1.1);
\draw[->,xshift=-2cm,rotate=32] (4.2,0)--(4.2,-1.45) node[name=v1,right=1pt,below=1pt] {$v_1$};     

%rectangle (5.7)        
\draw [xshift=-2cm,rotate=32] (5.6,-0.2) rectangle (5.8,0.2);   
\draw[->,xshift=-2cm,rotate=32] (6.0cm,0) arc (0:180:0.3cm) node[left=3pt,above=10pt] {$N_z$}; %arc 2
\draw[->,xshift=-2cm,rotate=32] (5.7,0)--(5.7,-1.4) node[right=1pt,below=1pt] {$v$}; %v

\filldraw[fill=black,xshift=-2cm,rotate=32] (7.2,0) circle (0.1cm); % M2
\draw[->,xshift=-2cm,rotate=32] (7.2,0)--(7.2,1);
\draw[->,xshift=-2cm,rotate=32] (7.2,0)--(7.2,-1.3) node[name =v2,right=1pt,below=1pt] {$v_2$};

\draw[->,xshift=-2cm,rotate=32] (5.7,0)--(5.7,0) node[name =c1] {$ $};
\draw[->,xshift=-2cm,rotate=32,rotate around={-32:(c1)}] (5.7,0)--(6.7,0) node[below] {$ F_xi $};
\draw[->,xshift=-2cm,rotate=32,rotate around={-32:(c1)}] (5.7,0)--(5.7,2) node[left] {$ F_xj $};        
\draw [dashed,xshift=-2cm,rotate=32] (4.2,-1.45)--(7.2,-1.3);

enter image description here

Reference: http://texdoc.net: pgf manual.

  • 2
    Please don't link to that manual, version 3 of TikZ is around five years old already. Link to CTAN (or texdoc.net) instead. Dec 15, 2018 at 16:05
  • 1
    (i) please, always provide complete small document, not only code fragment (ii) with your code (after adding extend it to mwe) i can't reproduce image showed in your answer.
    – Zarko
    Dec 16, 2018 at 1:16
  • @Zarko already improved, thank you, let me know if you have any questions about it.
    – Ben
    Dec 16, 2018 at 1:48
  • 1
    i saw your corrections :-). now works. well, meantime i write my suggestion how to draw your image. see if it can be helpful :-)
    – Zarko
    Dec 16, 2018 at 2:19
  • @Zarko thank you, it is very helpful :-). I spent much time drawing orthogonal vectors $F_xi$. your answer is simple than me, especially in readability of the code. I have an irrelevant question, how do you think about the Asymptote, I saw the document in the official site, is it more convenient in drawing 3d graphics?
    – Ben
    Dec 16, 2018 at 2:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.