1

Sorry for my bad English.

How can I removing space between bracket and array environment and obtained results as used cases environment.

Thank you very much!

I use code

\[\left\{\begin{array}{l} x + y = 1\\ x - y = 2 \end{array}\right.\]
\[\begin{cases} x+y=1 \\ x-y=2\end{cases}.\]

Pic 1 Pic 2

  • 2
    Following the \left\{, add \mkern-8mu or (approximate) \!\!\!. It is one reason why amsmath is preferred to array. – Steven B. Segletes Jan 11 at 14:52
  • 1
    or \begin{array}{@{}l}? – Troy Jan 11 at 14:54
  • It works well, thank you! – An Chu Văn Jan 11 at 14:55
1

Two options:

One with dedicated aligned environment. And, other by playing with the dedicated \mkern<space>. An example is as follows:

\documentclass[10pt,a4paper]{article}
\usepackage[latin1]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{graphicx}
\begin{document}
\[
    \left\{
    \begin{aligned}
     x + y = 1\\ x - y = 2
    \end{aligned}\right.
\]
    \[\left\{\mkern-10mu\begin{array}{l} x + y = 1\\ x - y = 2 \end{array}\right.\]
\end{document}

which would give you:

enter image description here

  • 1
    @Circumscribe you are very fast in commenting, than my typing speed :D – Raaja Jan 11 at 15:28
2

Here are two ways:

\documentclass[10pt,a4paper]{article}
\usepackage{mathtools, empheq}
\newtagform{eqt}{(eqt\,}{)}

\begin{document}

\[ \left\{\begin{array}{@{}l} x + y = 1 \\ x - y = 2 \end{array}\right.\]

\begin{empheq}[left=\empheqlbrace]{align*}
   x + y & = 1\\ x - y & = 2
\end{empheq}
\[\begin{cases} x+y=1 \\ x-y=2\end{cases}.\]

\end{document} 

enter image description here

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