How can i write the fractions in 1) so the numerator and denominator have the same height as the non-fraction in 2)
I'm using:
$1.\; \displaystyle{\lim_{x \to 1}}$ $\frac{x^2}{x-2}$ \\
$2.\; \displaystyle{\lim_{x \to 0}}$ $\tan(x+\pi/4)$ \\
This should work, but isn't well coded. Are you tring to do an enumeration of maths formulæ?
$1.\; \displaystyle\lim_{x \to 1}\frac{x^2}{x-2}$
$2.\; \displaystyle\lim_{x \to 0}\tan(x+\pi/4)$
-
ty, i had added the $ $ for a small space - what is the best way to add a small space between the limit and the fraction? ty – buffalo Jan 15 '19 at 0:14
-
Normally it is all taken care of by the system. If think it's as fine as you'd like, you may add a tin unbreakable space (
\,) between the limit and the fraction. – Bernard Jan 15 '19 at 0:22 -
-
-
@David Carlisle; Yes. 'Tis fixed. Actually, I didn't notice the O.P. used
\displaystyleas a command. Thanks! – Bernard Jan 15 '19 at 10:04
$1.\; \displaystyle{\lim_{x \to 1}}$ $\frac{x^2}{x-2}$to$1.\; \displaystyle{\lim_{x \to 1}}\frac{x^2}{x-2}$. (i.e. remove the two$in the middle). Actually, you should do this for both 1 and 2 anyway :-) – whatisit Jan 14 '19 at 23:51\displaystyle, if used correctly, will have two effects: (i) the fraction term will be typeset differently and (ii) the argument of\limwill be placed below rather than to the lower-right of "lim". – Mico Jan 15 '19 at 3:20