I am working on a presentation and would like to reuse the same table with the same label from the previous frame. I tried a lot of things, but did not have success. Attached u can find the frames and the code. Many thanks in forward.
\section{Conceptual Framework}
\begin{frame}
\frametitle{2. Conceptual Framework}
\begin{table}
\setlength{\extrarowheight}{2pt}
\begin{tabular}{cc|c|c|}
& \multicolumn{1}{c}{} & \multicolumn{2}{c}{Player 2}\\
& \multicolumn{1}{c}{} & \multicolumn{1}{c}{C} & \multicolumn{1}{c}{D} \\\cline{3-4}
\multirow{2}*{Player 1} & C & $b-c, b-c$ & $-c, b$ \\\cline{3-4}
& D & $b, -c$ & $0, 0$ \\\cline{3-4}
\end{tabular}
\caption{Prisoners' Dilemma}
\label{PD}
\end{table}
\begin{itemize}
\item{$b$ $>$ $c$ $>$ $0$}
\item{Given $c$ $>$ $0$, it is a dominant strategy to play D}
\item{Hence the NE of this game is (D,D) with payoff ($0$,$0$)}
\item{Since (C,C) gives $b$ - $c$ $>$ $0$, the equilibrium outcome (D,D) is inefficient}
\end{itemize}
\end{frame}
\begin{frame}
\frametitle{2. Conceptual Framework}
\begin{table}
\setlength{\extrarowheight}{2pt}
\begin{tabular}{cc|c|c|}
& \multicolumn{1}{c}{} & \multicolumn{2}{c}{Player 2}\\
& \multicolumn{1}{c}{} & \multicolumn{1}{c}{C} & \multicolumn{1}{c}{D} \\\cline{3-4}
\multirow{2}*{Player 1} & C & $b-c, b-c$ & $-c, b$ \\\cline{3-4}
& D & $b, -c$ & $0, 0$ \\\cline{3-4}
\end{tabular}
\renewcommand\thetable{\ref{PD}}
\caption{Prisoners' Dilemma}
\addtocounter{table}{-1}
\end{table}
\end{frame}
\item Given $c$ $>$ $0$, it is a dominant strategy to play D
(without the{}
around)