3

I am using blkarray to generate a labelled matrix. I would like to indicate the transpose of such matrix using a superscript with T. However I cannot find the right syntax to get what I want. Below you can find my attempts.

\documentclass{article}
\usepackage{blkarray}
\usepackage{amsmath,bm,amssymb}

\begin{document}

\begin{equation}
\begin{blockarray}{ccccccc}
1 & & 12 & 13 & 14 & 15 & 16\\
\begin{block}{(ccccccc)}
0 & \cdots & 0 & 1 & 1 & 1 & 1\\
\end{block}
\end{blockarray}^T
\end{equation}

\end{document}

enter image description here

\documentclass{article}
\usepackage{blkarray}
\usepackage{amsmath,bm,amssymb}

\begin{document}

\begin{equation}
\begin{blockarray}{ccccccc}
1 & & 12 & 13 & 14 & 15 & 16\\
\begin{block}{(ccccccc)}
0 & \cdots & 0 & 1 & 1 & 1 & 1\\
\end{block}^T
\end{blockarray}
\end{equation}

\end{document}

enter image description here

\documentclass{article}
\usepackage{blkarray}
\usepackage{amsmath,bm,amssymb}

\begin{document}

\begin{equation}
\begin{blockarray}{cccccccc}
1 & & 12 & 13 & 14 & 15 & 16 &\\
\begin{block}{(ccccccc)c}
0 & \cdots & 0 & 1 & 1 & 1 & 1 & ^T\\
\end{block}
\end{blockarray}
\end{equation}

\end{document}

enter image description here

How can I get the superscript nicely, as if the matrix was not generated with blkarray?

  • 1
    Yes, it should be a superscript to the closing bracket, same position that you get when applying a superscript to a pmatrix environment for example. – Francesco Jan 23 at 16:07
2

Something like this?

\documentclass{article}
\usepackage{blkarray}

\begin{document}

\begin{equation}
\begin{blockarray}{cccccccc}
1 & & 12 & 13 & 14 & 15 & 16 &\\
\begin{block}{(ccccccc)@{\hphantom{)}}l}
0 & \cdots & 0 & 1 & 1 & 1 & 1 & {\vphantom{)}}^T\\
\end{block}
\end{blockarray}
\end{equation}
\end{document}

enter image description here

  • Nice! May I ask you what \hphantom and \vphantom do in the syntax? – Francesco Jan 23 at 16:14
  • 1
    @Francesco \hphantom{)} inserts an empty horizontal space/symbol that is as wide as ), and \vphantom{)} inserts and empty symbol that is as high as ). You can put any symbol in the arguments of these phantoms. (There is alos \phantom which inserts an "empty" symbol.) – marmot Jan 23 at 16:17
  • Thanks @marmot. So basically \begin{block}{(ccccccc)@{\hphantom{)}}l} indicates the beginning of a block with 7 centered elements enclosed by brackets followed by left-aligned element having the same horizontal width of )? – Francesco Jan 23 at 16:36
  • 1
    @Francesco Almost. @{\hphantom{)}}l says this is a left-aligned column with horizontal space as wide as ) in the beginning. You could also say \begin{block}{(ccccccc)@{}l} 0 & \cdots & 0 & 1 & 1 & 1 & 1 & {\phantom{)}}^T\\ \end{block} to achieve the same. – marmot Jan 23 at 16:40
0

Set the indices using a smaller font:

enter image description here

\documentclass{article}

\usepackage{array}

\begin{document}

\[
  \begin{tabular}{c}
    \mbox{\scriptsize\begin{tabular}{ *{7}{>{\centering}p{10pt}} }
      1 &  & 12 & 13 & 14 & 15 & 16
    \end{tabular}} \\
    \begin{tabular}{ *{7}{>{\centering}p{10pt}} }
      \makebox[0pt][r]{$\bigl($}%
      0 & $\cdots$ & 0 & 1 & 1 & 1 & 1%
      \makebox[0pt][l]{$\bigr)^T$}
    \end{tabular}
  \end{tabular}
\]

\end{document}

Above I use a tabular with fixed-width columns, setting elements inside p{10pt} columns. You can use zero-width boxes in the outer-columns to simulate a matrix-style (...)^T.

0

Do you need blockarray at all?

\documentclass{article}
\usepackage{amsmath}

\newcommand{\IND}[2]{\overset{#2\vphantom{\smash[t]{\Big|}}}{#1}}

\begin{document}

\begin{equation}
\bigl(\IND{0}{1} \quad \cdots \quad \IND{0}{12} \quad
\IND{1}{13} \quad \IND{1}{14} \quad \IND{1}{15} \quad \IND{1}{16}\bigr)^T
\end{equation}

\end{document}

enter image description here

Alternative version:

\documentclass{article}
\usepackage{amsmath}

\newcommand{\IND}[2]{%
  \vbox{\ialign{%
    \hfil$##$\hfil\cr
    \scriptstyle#2\cr
    #1\cr
  }}%
}

\begin{document}

\begin{equation}
\bigl(\IND{0}{1} \quad \cdots \quad \IND{0}{12} \quad
\IND{1}{13} \quad \IND{1}{14} \quad \IND{1}{15} \quad \IND{1}{16}\bigr)^T
\end{equation}

\end{document}

enter image description here

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