When I delete the second \item, it compiles fine. However, with the second \item, I get ERROR: Missing $ inserted and the math renders incorrectly:
\documentclass[12pt]{article}
\newcommand \frob[2] {\langle #1,#2 \rangle_F}
\begin{document}
\begin{itemize}
\item What I want: $
\langle A,B \rangle_F
\geq
\langle C,D \rangle_F
$.
\item What I get: $
\frob{A,B}
\geq
\frob{A,B}
$.
\end{itemize}
\end{document}
Would appreciate any help with this issue!
You defined \frob to take two arguments
\newcommand{\frob}[2]
However, you're only passing it one argument when you use it like this
\frob{A,B}
That's because arguments are specified as tokens or using braces {...}, not a comma-separated list of elements.
Since you're printing the same thing as you're passing, the following might be simpler:
\documentclass{article}
\newcommand{\frob}[1]{\langle #1 \rangle_F}
\begin{document}
\begin{itemize}
\item
What I want: $
\langle A,B \rangle_F
\geq
\langle C,D \rangle_F
$.
\item
What I get: $
\frob{A,B}
\geq
\frob{A,B}
$.
\end{itemize}
\end{document}
If you really want to pass two arguments, then your definition should be
\newcommand{\frob}[2]{\langle #1, #2 \rangle_F}
and you'll use it via \frob{A}{B}.
\frac that way, but somehow had a brain fart when defining my own function. Thanks!
– Elliot Gorokhovsky
Feb 2 at 22:13
\frobas\frob{A,B}but use it as\frob{A}{B}. Your\frob-macro does process two arguments which are not comma-separated. As result it delivers something where the phrases delivered via the arguments will be comma-separated. Maybe this confused you. ;-) If you do\frob{A,B}\geq,\frob's first undelimited argument will be formed from{A,B}and\frob's second undelimited argument will be formed from\geq. So all in all\frob{A,B} \geq \frob{A,B}should be\frob{A}{B}\geq\frob{C}{D}. – Ulrich Diez Feb 2 at 1:45