I am writing the following equation to put a dot on a bold symbol math character but the dot does not show up; however, this works in the IEEEtran format.


% defining the \BibTeX command - from Oren Patashnik's original BibTeX documentation.
\def\BibTeX{{\rm B\kern-.05em{\sc i\kern-.025em b}\kern-.08emT\kern-.1667em\lower.7ex\hbox{E}\kern-.125emX}}

% Rights management information. 
% This information is sent to you when you complete the rights form.
% These commands have SAMPLE values in them; it is your responsibility as an author to replace
% the commands and values with those provided to you when you complete the rights form.
% These commands are for a PROCEEDINGS abstract or paper.
\acmConference[CPS-SR '19]{CPS-SR '19: Cyber-Physical Systems and Internet-of-Things Week}{April 15--19, 2019}{Montreal, Canada}
\acmBooktitle{CPS-SR '19: 2$^\text{nd}$ Workshop on Cyber-Physical Systems Security and Resilience, April 15--19, 2019, Montreal, Canada}

\usepackage{amsmath, amsfonts, amssymb, color, enumerate, amsthm, graphicx, mathtools}
\usepackage{tikz, subcaption}
\usepackage{color, xcolor, soul, bm}
    colorlinks   = true, %Colours links instead of ugly boxes
    urlcolor     = blue, %Colour for external hyperlinks
    linkcolor    = blue, %Colour of internal links
    citecolor   = green %Colour of citations


%\newcommand{\ShS}[1]{$\clubsuit$\footnote{SHREYAS: #1}}
%\newcommand{\mathcolorbox}[2]{\colorbox{#1}{$\displaystyle #2$}}


% These commands are for a JOURNAL article.

% Submission ID. 
% Use this when submitting an article to a sponsored event. You'll receive a unique submission ID from the organizers
% of the event, and this ID should be used as the parameter to this command.

% The majority of ACM publications use numbered citations and references. If you are preparing content for an event
% sponsored by ACM SIGGRAPH, you must use the "author year" style of citations and references. Uncommenting
% the next command will enable that style.

% end of the preamble, start of the body of the document source.
$\boldsymbol{\tilde{x}} = [\mathbf{\tilde{P}} \quad \mathbf{\dot{\tilde{P}}}]^{\sf T}=[\tilde{p}_1, \tilde{p}_2, \ldots, \tilde{p}_n, \dot{\tilde{p}}_1, \dot{\tilde{p}}_2, \ldots, \dot{\tilde{p}}_n]^{\sf T}$

This the result in which the red P does not have a dot on top of it,

enter image description here

1 Answer 1


try the following:


    = [\tilde{\mathbf{P}} \quad \dot{\tilde{\mathbf{P}}}]^\intercal
    = [\tilde{p}_1, \tilde{p}_2, \ldots, \tilde{p}_n,
       \dot{\tilde{p}}_1, \dot{\tilde{p}}_2, \ldots, \dot{\tilde{p}}_n]^\intercal

or with use of the \verb+\bigl[+ and \verb+\bigr]+ for square brackets 

delimiters (as suggest @egreg in his comment):

    = \Bigl[\tilde{\mathbf{P}} \quad \dot{\tilde{\mathbf{P}}}\Bigr]^\intercal
    = \Bigl[\tilde{p}_1, \tilde{p}_2, \ldots, \tilde{p}_n,
            \dot{\tilde{p}}_1, \dot{\tilde{p}}_2, \ldots, \dot{\tilde{p}}_n\Bigr]^\intercal

enter image description here

  • Not with \left and \right, please.
    – egreg
    Commented Feb 7, 2019 at 9:52
  • @egreg, it is convenient ... is not needed to search for right size of \bigl or `\Bigl˙, ... :-). now corrected (but not sure, if i select correct ones, so i left selection to op).
    – Zarko
    Commented Feb 7, 2019 at 11:35
  • Delimiters need not cover the whole thing, accents in particular. Possibly \big size could do, but in this case, normal size is the best, in my opinion, and \left-\right produce an awful output.
    – egreg
    Commented Feb 7, 2019 at 11:41
  • @egreg, done :-)
    – Zarko
    Commented Feb 7, 2019 at 12:36

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