# How to write equation as shown in picture using Latex? how we write this equation in latex in given form

• Nice try, but even the most comprehensive answer won't help you much. You won't get written all of your equations here. Learn LaTeX. Read an introduction and the command texdoc packagenameis a great help. Feb 14, 2019 at 11:58
• Welcome to Stack Exchange! It looks like there's already a few solutions posted below. Great. However may I suggest that next time you ask a question, mention what you have already tried. e.g. Have you figured out how to write a gamma on its own? Have you figured out how to write a fraction? How to write du/dz? etc. The more effort you demonstrate you have put in, the more effort others will be willing to put in for you. It also helps us understand precisely which part of the task you need help with. Feb 15, 2019 at 4:49
• I have downvoted, because this question does not show any research effort. Feb 15, 2019 at 8:08
• Here is the solution given by the powerful Mathpix Snipping Tool $u \frac{\partial u}{\partial x}+v \frac{\partial u}{\partial y}+w \frac{\partial u}{\partial z}+\lambda_{1}\left(\begin{array}{c}u^{2} \frac{\partial^{2} u}{\partial x^{2}}+v^{2} \frac{\partial^{2} u}{\partial y^{2}}+w^{2} \frac{\partial^{2} u}{\partial z^{2}} \\ +2 u v \frac{\partial^{2} u}{\partial x \partial y}+2 v w \frac{\partial^{2} u}{\partial y \partial z}+2 u w \frac{\partial^{2} u}{\partial x \partial \tilde{z}}\end{array}\right)=\nu \frac{\partial^{2} u}{\partial z^{2}}$. Apr 27, 2021 at 18:27

With a few shortcut macros it's much easier:

plain TeX version:

\let~\catcode~86~j0~X13~C1~D2~M3jdefX81C~8113jdefDXZZ81C~
8113DXYY81CZ81jletDYLLjletYFFjfiYNNjdefYPPjpartialZIZAZBZj{Zj}Y
EEjexpandafterYOOjelseYKKjifxNI818283CL}81NAC82DNBC83Djfuturelet
jTjHDNjHCKjT}L{AOL{BF{DXUUCI)jpCjp)CDDDY VVjoverNjp)818283CKX81X
CP82VP83DOCP^C81D82VjbC81DC83DDFDYRRjrelaxNjb8182Cjd8182RDNjd81%
8283CK83RP82^C81DOP82P83FDY!!uY@@vY##wY$$xYj%%yY&&zXvv81C81^2DMM !U!+@U!%+#U!&+jlambda_1jleft(v!U)2! +v@U)2!%+v#U)2!&jatop+2!@U )2!C%D+2@#U)2!C%&D+2!#U)2!C&Djright)=jnuU)2!&jeqno(1.25)MMjbye  LaTeX version: \documentclass{article}\begin{document} \let~\catcode~86~j0~X13~C1~D2~M3jdefX81C~8113jdefDXZZ81C~ 8113DXYY81CZ81jletDYLLjletYFFjfiYNNjdefYPPjpartialZIZAZBZj{Zj}Y EEjexpandafterYOOjelseYKKjifxNI818283CL}81NAC82DNBC83Djfuturelet jTjHDNjHCKjT}L{AOL{BF{DXUUCI)jpCjp)CDDDY VVjoverNjp)818283CKX81X CP82VP83DOCP^C81D82VjbC81DC83DDFDYRRjrelaxNjb8182Cjd8182RDNjd81% 8283CK83RP82^C81DOP82P83FDY!!uY@@vY##wY$$xYj%%yY&&zXvv81C81^2DMM
!U!$+@U!%+#U!&+jlambda_1jleft(v!U)2!$+v@U)2!%+v#U)2!&jatop+2!@U)
2!C$%D+2@#U)2!C%&D+2!#U)2!C$&Djright)=jnuU)2!&jeqno(1.25)MMjstop


output: Inspired by David Carlisle's xii :)

• +1 for snarkiness. Feb 14, 2019 at 22:32
• I don't think MiKTeX gave me a TeX engine. May 20, 2019 at 21:09
• @ahorn Sorry, I don't understand what you mean. You didn't find the tex executable? May 20, 2019 at 21:11
• @PhelypeOleinik I just don't know how to run TeX code, so I thought I'd leave a comment. Sorry for the clutter. May 20, 2019 at 21:52
• @ahorn No worries, we can delete them later :-) Do you run LaTeX from the command line or from an IDE? If the latter, then which one? TeXMaker? TeXStudio? Another? May 20, 2019 at 23:59

A variation on the theme, but with a greater emphasis on simplifying the input:

\documentclass{article}
\usepackage{amsmath}
\usepackage{xparse}

\newcommand{\pdiff}{\mathop{}\!\partial}

\ExplSyntaxOn
\NewDocumentCommand{\pder}{omm}
{
\frac{\pdiff\IfValueT{#1}{^{#1}}#2}{\faisal_pder_vars:n { #3 }}
}
\cs_new_protected:Nn \faisal_pder_vars:n
{
\clist_map_inline:nn { #1 } { \pdiff##1 }
}
\ExplSyntaxOff

\begin{document}

\begin{equation}
u\pder{u}{x}+v\pder{u}{y}+w\pder{u}{z}+
\lambda_1
\left(\begin{gathered}
u^2\pder{u}{x^2}+v\pder{u}{y^2}+w^2\pder{u}{z^2}\\
\mspace{-\medmuskip}{}
+2uv\pder{u}{x,y}+2vw\pder{u}{y,z}+2uw\pder{u}{x,z}
\end{gathered}\right)
= \nu\pder{u}{z^2},
\end{equation}

\begin{equation}
\begin{split}
u\pder{u}{x}&+v\pder{u}{y}+w\pder{u}{z}
+\lambda_1\biggl(
u^2\pder{u}{x^2}+v\pder{u}{y^2}+w^2\pder{u}{z^2}
\\
&+2uv\pder{u}{x,y}+2vw\pder{u}{y,z}+2uw\pder{u}{x,z}\biggr)
= \nu\pder{u}{z^2},
\end{split}
\end{equation}

\end{document}


The syntax for \pder is

1. optional argument for the order of the derivative (if greater than 1)
2. function to differentiate
3. list of the variables the derivative is taken with respect to, comma separated

In the first case I used \mspace{-\medmuskip}{}+ in order to have the plus sign correctly spaced. I used gathered instead of pmatrix because it is semantically sounder. Here you go:

\documentclass[10pt,a4paper]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{graphicx}
\begin{document}
$u\frac{\partial u}{\partial x}+v\frac{\partial u}{\partial y}+w\frac{\partial u}{\partial z}+\lambda_1\begin{pmatrix} u^2\frac{\partial^2 u}{\partial x^2}+v\frac{\partial^2 u}{\partial y^2}+w^2\frac{\partial^2 u}{\partial z^2}\\+2uv\frac{\partial^2 u}{\partial x\partial y}+2vw\frac{\partial^2 u}{\partial y\partial z}+2uw\frac{\partial^2 u}{\partial x\partial z} \end{pmatrix} = v\frac{\partial^2 u}{\partial z^2},$
\end{document}


this will give you: PS: Welcome to TeX.se, from next time, please provide a MWE.

Here is a start:

\documentclass[]{article}
\usepackage{amsmath}

\begin{document}
\begin{equation}
u\frac{\partial u}{\partial x}+...
+\lambda_1
\begin{pmatrix}
u^2 \frac{\partial^2 u}{\partial x^2}+...\\
+ 2 uv \frac{\partial^2 u}{\partial x \partial y}+...
\end{pmatrix} = v \frac{\partial^2 u}{\partial z^2}
\end{equation}
\end{document} • Please, edit your code and replace ... by \dots (or \cdots when not between two plus signs). Feb 14, 2019 at 13:20
• @Sigur I have added the three dots to indicate to OP that he has to complete the equation by himself. The final version of the equation should not have dots within it. Feb 14, 2019 at 16:59

Borrow a little from all answer and make a little change (such as change v to \nu in the right-hand side)

\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
u\frac{\partial u}{\partial x}+v\frac{\partial u}{\partial y}+w\frac{\partial u}{\partial z}+\lambda_1\begin{pmatrix}
u^2\frac{\partial^2 u}{\partial x^2}+v\frac{\partial^2 u}{\partial y^2}+w^2\frac{\partial^2 u}{\partial z^2}\\+2uv\frac{\partial^2 u}{\partial x\partial y}+2vw\frac{\partial^2 u}{\partial y\partial z}+2uw\frac{\partial^2 u}{\partial x\partial z}
\end{pmatrix} = \nu\frac{\partial^2 u}{\partial z^2},
\tag{1.25}
\end{equation}
\end{document} \documentclass{article}

\begin{document}
$u \frac{\partial u}{\partial x} + v \frac{\partial u}{\partial y}+ w \frac{\partial u}{\partial z} + \lambda_1 \left( \begin{tabular}{c} \:\:\:\:\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2}\\ + 2 u v \frac{\partial^2 u}{\partial x \partial y}+ 2vw \frac{\partial^2 u}{\partial y\partial z}+2wu \frac{\partial^2 u}{\partial z \partial u}\\\end{tabular} \right) = \nu \frac{\partial^2 u}{\partial z^2}$
\end{document}


This gives desired output.

$$u \frac{\partial u}{\partial x}+v \frac{\partial u}{\partial y}+w \frac{\partial u}{\partial z}+\lambda_{1}\left(\begin{array}{c} u^{2} \frac{\partial^{2} u}{\partial x^{2}}+v^{2} \frac{\partial^{2} u}{\partial y^{2}}+w^{2} \frac{\partial^{2} u}{\partial z^{2}} \\ +2 u v \frac{\partial^{2} u}{\partial x \partial y}+2 v w \frac{\partial^{2} u}{\partial \partial \partial z}+2 u w \frac{\partial^{2} u}{\partial x \partial z} \end{array}\right)=\nu \frac{\partial^{2} u}{\partial z^{2}}$$

• Hi and welcome. I didn't downvote for your answer. Please, expand your answer by giving fully compilable code starting with \documentclass{} and ending with \end{document} Aug 9, 2020 at 18:27