# Draw curve in the plane by using tikz

I would like to represent a curve in the plane (i.e. a continuous map from a one-dimensional space to a 2-dimensional space). The (parametric) equation of the curve is (x,y)=(f(t),g(t)) where t real and f,g two fuctions of t. These two functions are too complicated to be written here but my question does not depend on their forms, because I would like to draw this curve by using tikz. How do I do that?

EDIT For example, the following code:

\begin{tikzpicture}
\begin{axis}[samples y=0]
\addplot3+[domain=0:1] (x,x^2,x^3);
\end{axis}
\end{tikzpicture}


works well on three dimensional space. But how I could use it for the plane?

• Well, if f and g are too complicated to be written, how would you tell TikZ what to plot? You can easily plot curves in a plane e.g. using tikz-3dplot and the 3d library but you need to know what you want to plot. – user121799 Mar 25 at 18:07
• Your plot in the example has three coordinates (x, x^2, x^3) so you will have to do a change of axis to plot it in 2 dimensions? – RockyRock Mar 25 at 18:30

## 1 Answer

You can parametrize with t your function in (x,y,z) as follows:

\documentclass{article}
\usepackage{tikz}
\usepackage{pgfplots}
\pgfplotsset{compat=newest}

\begin{document}
\begin{tikzpicture}
\begin{axis}[width=0.75*\textwidth,
axis lines=left,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=0,
zmax=1,
ticks=none,
view={240}{20},
unbounded coords=jump,
z filter/.expression={z>1 ? nan : z},
restrict z to domain*=0:1]
\addplot3[variable=t, mesh, draw=black!50, domain=-1:1] ({t^2},{t},1);
\end{axis}
\end{tikzpicture}
\end{document} Or in two dimensions

  \documentclass{article}
\usepackage{tikz}
\usepackage{pgfplots}
\pgfplotsset{compat=newest}

\begin{document}
\begin{center}
\begin{tikzpicture}
\begin{axis}
\addplot[blue, samples=40, variable=\t, domain=0:4]
({125*t*cos(deg(30)))},
{3+125*t*sin(deg(30))-16*t^2});
\end{axis}
\end{tikzpicture}
\end{center}
\end{document} Hope that helps!

Romain

• Thank you RockyRock! I updated my post. – Mark Mar 25 at 18:18