Change appearance of voltage source in circuitikz

Question

I prefer my voltage sources as in the image below. How can I achieve this in circuitikz?

There is an identical question here, however for plain tikz. I tried to implement the solution given their, but it does not seem to work in combination with circtuitikz. In fact it generates an error.

Answer 1

One simple approach is to use open with o-o option:

\draw (0,0) to ++(1,0) to[open,o-o,l={$U_\sim$}] ++(1,0) to ++(1,0);

Or else, custom component customV can be defined and used:

\draw (3.5,0) to[customV,l={$U_\sim$}] ++(3,0);

MWE:

\documentclass[border=3mm]{standalone}
\usepackage{circuitikz}

\makeatletter
\pgfcircdeclarebipole{}{\ctikzvalof{bipoles/open/height}}{customV}{\ctikzvalof{bipoles/open/height}}{\ctikzvalof{bipoles/vsource/width}}{
    \pgftransformshift{\pgfpoint{\pgf@circ@res@left}{0pt}}
    \pgfnode{ocirc}{center}{}{}{\pgfusepath{draw}}
    \pgftransformshift{\pgfpoint{2\pgf@circ@res@right}{0pt}}
    \pgfnode{ocirc}{center}{}{}{\pgfusepath{draw}}
}
  \def\pgf@circ@customV@path#1{\pgf@circ@bipole@path{customV}{#1}}
  \compattikzset{customV/.style = {\circuitikzbasekey, /tikz/to path=\pgf@circ@customV@path, label=#1}}
\makeatother

\begin{document}
\begin{circuitikz}
\draw (0,0) to ++(1,0) to[open,o-o,l={$U_\sim$}] ++(1,0) to ++(1,0);
\draw (3.5,0) to[customV,l={$U_\sim$}] ++(3,0);
\end{circuitikz}
\end{document}