3

I understand how to align multiple equations, but how can I do this if I want to also have text over the equalities. For example:

enter image description here

It bugs me that the equal signs are no longer aligned. Here is my LaTeX:

$$
\begin{align}
p(\textbf{x} \mid \mathcal{D}, \alpha)
&= \int p(\textbf{x} \mid \boldsymbol{\theta}) p(\boldsymbol{\theta} \mid \mathcal{D}, \alpha) \text{d} \boldsymbol{\theta}
\\
&\stackrel{\text{Eq 4}}{=} \int p(\textbf{x} \mid \boldsymbol{\theta}) p(\boldsymbol{\theta} \mid \alpha') \text{d} \boldsymbol{\theta}
\\
&= p(\textbf{x} \mid \alpha'). \tag{5}
\end{align}
$$

Is there a solution to this?

  • Off-topic: Encasing an align environment inside $$ ... $$ cannot possibly work correctly -- at least not as a LaTeX document. Please be more precise about you actually do. – Mico Apr 16 at 18:47
  • Fair point. I'm technically using MathJax, which requires this to work, but I should have edited it for the post. – gwg Apr 16 at 20:34
  • MathJax (used on this site) works with align without $$ $$. – Bernard Apr 16 at 20:39
4

Here I use \mathclap to insure that the overstack takes up zero horizontal space.

Also, change the \textbf instances to \mathbf (thanks, Mico).

Finally, ditch the $$ delimiters.

\documentclass{article}
\usepackage{mathtools}
\begin{document}

\begin{align}
p(\mathbf{x} \mid \mathcal{D}, \alpha)
&= \int p(\mathbf{x} \mid \boldsymbol{\theta}) p(\boldsymbol{\theta} \mid \mathcal{D}, \alpha) \text{d} \boldsymbol{\theta}
\\
&\stackrel{\mathclap{\text{Eq 4}}}{=} \int p(\mathbf{x} \mid \boldsymbol{\theta}) p(\boldsymbol{\theta} \mid \alpha') \text{d} \boldsymbol{\theta}
\\
&= p(\mathbf{x} \mid \alpha'). \tag{5}
\end{align}


\end{document}

enter image description here

1

A simple \makebox[0pt]{...} will solve the probl.

Unrelated: do not nest align inside $$ ... $$ – and don't use the plain TeX construct ˆˆ ... $$ as it will yield incorrect spacing in LaTeX.

\documentclass{article}
\usepackage{amsmath}

\begin{document}

\begin{align}
p(\textbf{x} \mid \mathcal{D}, \alpha)
&= \int p(\textbf{x} \mid \boldsymbol{\theta}) p(\boldsymbol{\theta} \mid \mathcal{D}, \alpha) \text{d} \boldsymbol{\theta}
\\
&\stackrel{\text{\makebox[0pt]{Eq 4}}}{=} \int p(\textbf{x} \mid \boldsymbol{\theta}) p(\boldsymbol{\theta} \mid \alpha') \text{d} \boldsymbol{\theta}
\\
&= p(\textbf{x} \mid \alpha'). \tag{5}
\end{align}

\end{document} 

enter image description here

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.