This question does not ask the user to provide me a full MWE, but simply to obtain any information step by step as to create different circular sectors.

enter image description here This image is taken from the site: https://www.inrim.it/sites/default/files/mediaroot/eventi/logo_nuovosi.png

I have read the only the manual pgf-pie to build pie charts and with lot of sincerity I have seen the responses of users and I have been so scared (see here: Multi-layer Donut Pie).

In fact, I was wondering if you need very much code to make a frontal one that is not in 3D.

I would like to make it because I absolutely don't like some symbols like $\Delta v$ and $K_{\text{cd}}$.

So I only ask users for the simplest steps and no complete MWE.

Thank you (excuse me very much for not having added the link of the image and I have not specified that it serves only me and will not be published, or used improperly).

  • 6
    You should probably cite where you copied that image (I assume bipm.org/utils/common/img/rev-si/SI-7.jpg) The usual advice for logos is that it is a bad idea to fake them (and it may be trademark infringement) the whole point of a logo is that it is an instantly recognisable graphic denoting whatever it denotes. – David Carlisle May 26 '19 at 8:56
  • @DavidCarlisle I'm so sorry, David. I forgot to insert the link to the image. I sincerely hope that I have not done any more damage. I wanted to see if there was any particular manual for creating circular sectors. I would like to point out once again that I was interested in creating it by myself, understanding the necessary steps; I thought that there were some specific packages. I don't know whether or not to remove the question. I'm waiting for instructions. Hello and thank you. – Sebastiano May 26 '19 at 11:32

The following code seems sufficiently simple and solves the rotation issue with the letters in the bottom blocks.





% -----------------------------------
% the \foreach-part
    [evaluate={\n as \p         using int((\n-3)*(\n-4))},
     evaluate={\n as \angle     using (90+360/14-360/7*\n)},
     evaluate={\n as \Angle     using (90+360/14-360/7*(\n+1))},
     evaluate={\n as \nsegment  using (360/7*\n)}
    {0  /red/kg/$h$,
     1  /orange/m/$c$,
     2  /yellow/s/$\Delta v$,
     3  /Green/A/$e$,
     4  /RoyalBlue/K/$k$,
     5  /violet/mol/$N_A$,
     6  /Blue/cd/$K_{\textnormal{\scriptsize cd}}$%
    {\fill[draw=white,line width=2.5pt,fill=\k!90!black,domain=\angle:\Angle,variable=\t]
        plot ({2*cos(\t)},{2*sin(\t)})
        -- (0,0)
        -- cycle;
        plot ({1.2*cos(\t)},{1.2*sin(\t)})
        -- (0,0)
        -- cycle;
            node[white,rotate=180-\nsegment] at (90-\nsegment:1.6) {\l}
            node[rotate=180-\nsegment,font=\small] at (90-\nsegment:.95) {\o};
            node[white,rotate=-\nsegment] at (90-\nsegment:1.6) {\l}
            node[font=\small,rotate=-\nsegment] at (90-\nsegment:.95) {\o};
% -----------------------------------
\node[circle,font=\huge,fill=white,inner sep=7pt] (0,0) {SI};

enter image description here

  • Marian thank you very much :-( and I thank you for your response. I certainly didn't ask for an MWE as beautiful as yours, but to understand how it came about. I thought that with the only package I knew you could do. Thank you very much. – Sebastiano May 26 '19 at 11:28
  • 1
    +1 Mich nicer than mine. – Andrew May 26 '19 at 12:39

Perhaps something like this:

enter image description here

You can get the colours of your logo by looking through the xcolor manual. If you really want the K, A and s rotated as in the OP this can be done but the rotations below are more natural.

Here is the code:

\documentclass[tikz, border=2mm]{standalone}


    \foreach \top/\mid/\col [count=\c,
                  evaluate=\c as \st using {360/7*(\c-1)+1},
                  evaluate=\c as \en using {360/7*\c-1},
                  evaluate=\st as \se using {(\st+\en)/2}
    ] in {m/c/orange,
          S/\Delta v/yellow} {
       \draw[\col,fill=\col!80] (\st:1)--(\st:2)
           arc [start angle=\st, end angle=\en, radius=2]
           arc [start angle=\en, end angle=\st, radius=1];
       \draw[\col,fill=\col!50] (\st:0.5)--(\st:1)
           arc [start angle=\st, end angle=\en, radius=1]
           arc [start angle=\en, end angle=\st, radius=0.5];
       \node[white,rotate=\se-90,font=\bfseries] at (\se:1.5){\top};
       \node[rotate=\se-90,font=\scriptsize] at (\se:0.75){$\mid$};

  • do you find it natural if "6" is upside-down on a clockface? :-) – David Carlisle May 26 '19 at 11:04
  • I'm so sorry I had you create a code. I'm sorry again just wanted to understand if there was a strategy with packages to use, but you just need a reasoning with tikz-pgf. I thank you very much. – Sebastiano May 26 '19 at 11:34
  • @DavidCarlisle No more than a "9" being he right way up:) In such instances one has to infer the meaning from the orientation of related text. – Andrew May 26 '19 at 12:37
  • 1
    @DavidCarlisle reminds me of that old joke "Come in boat number 9, oops number six are you in trouble ? – user170109 May 26 '19 at 16:17
  • 2
    Possible typo : K_{cd} – Karlo May 26 '19 at 19:40

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