1

This is essentially the same question as this, this or this, but in all three questions the picture that defines the new coordinates is positioned at (0, 0) of the tikzpicture. In my case it is not.

MWE:

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{fit,calc}

\pagestyle{empty}
\usepackage{parskip}

\begin{document}
    \begin{tikzpicture}
        \coordinate (TL) at (1+.3*rand,4+.3*rand);
        \coordinate (BR) at (6+.3*rand,1+.3*rand);
        \node [draw,fit=(TL) (BR)]{Background};
        \begin{scope}
            \node at (5,5) {X};
        \end{scope}
    \end{tikzpicture}
\end{document}

screenshot

As an example, how can I set up a coordinate system (0..10) inside the node so that (5,5) is in the middle of the box?

1

You only need to shift to the south west corner of the coordinate system.

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{fit,calc}

\pagestyle{empty}
\usepackage{parskip}

\begin{document}
    \begin{tikzpicture}
        \coordinate (TL) at (1+.3*rand,4+.3*rand);
        \coordinate (BR) at (6+.3*rand,1+.3*rand);
        \node [draw,fit=(TL) (BR)] (fit) {Background};
        \begin{scope}[shift={(fit.south west)},
        x={($0.1*($(fit.south east)-(fit.south west)$)$)},
        y={($0.1*($(fit.north west)-(fit.south west)$)$)}]
            \node at (5,5) {X};
        \end{scope}
    \end{tikzpicture}
\end{document}

enter image description here

  • Oh, nested calculation. – AndreKR Jun 10 at 18:51

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.