1

Problem:

I have a long text that is split into two sentences in a enumerate list. I wish for the text to be vertically center aligned with the item.

Minimal Working Example (MWE):

\documentclass{article}
\usepackage{enumitem}
\usepackage{amsmath}

\begin{document}

\noindent
\begin{enumerate}[label=\textbf{\arabic*}), itemsep=3ex]
  \item $\dfrac{3x + 1}{x - 1} \geq \dfrac{6x - 2}{x + 2} \Leftrightarrow \dfrac{3x + 1}{x - 1} - \dfrac{6x - 2}{x + 2} \geq 0 \Leftrightarrow (MGN = (x - 1)(x + 2))$
  \item[] $\Leftrightarrow \dfrac{(3x + 1)(x + 2)}{(x - 1)(x + 2)}-\dfrac{(6x - 2)(x - 1)}{(x + 2)(x - 1)} \geq 0 \Leftrightarrow$ (This is a short sentence.)
  \item[] $\Leftrightarrow \dfrac{(3x + 1)(x + 2) - (6x - 2)(x - 1)}{(x - 1)(x + 2)} \geq 0 \Leftrightarrow$ (This is a long sentence that needs be beneath itself.)
  \item[] $\Leftrightarrow \dfrac{3x^{2} + 7x + 2 - \left(6x^{2} - 8x + 2\right)}{(x - 1)(x + 2)} \geq 0 \Leftrightarrow R(x) = \dfrac{-3x^{2} + 15x}{(x - 1)(x + 2)} \geq 0$
\end{enumerate}
\end{document}

Current output:

enter image description here

Desired output:

The text This is a long sentence that needs be beneath itself. should be under itself aligned vertically center to the right of the double arrow.

2

enter image description here

\documentclass{article}
\usepackage{enumitem}
\usepackage{amsmath}

\begin{document}

%? \noindent
\begin{enumerate}[label=\textbf{\arabic*}), itemsep=3ex]
  \item $\dfrac{3x + 1}{x - 1} \geq \dfrac{6x - 2}{x + 2} \Leftrightarrow \dfrac{3x + 1}{x - 1} - \dfrac{6x - 2}{x + 2} \geq 0 \Leftrightarrow (MGN = (x - 1)(x + 2))$
  \item[] $\Leftrightarrow \dfrac{(3x + 1)(x + 2)}{(x - 1)(x + 2)}-\dfrac{(6x - 2)(x - 1)}{(x + 2)(x - 1)} \geq 0 \Leftrightarrow$ (This is a short sentence.)
  \item[] $\Leftrightarrow \dfrac{(3x + 1)(x + 2) - (6x - 2)(x - 1)}{(x - 1)(x + 2)} \geq 0 \Leftrightarrow$ \parbox{4cm}{\centering (This is a long sentence that needs be beneath itself.)}
  \item[] $\Leftrightarrow \dfrac{3x^{2} + 7x + 2 - \left(6x^{2} - 8x + 2\right)}{(x - 1)(x + 2)} \geq 0 \Leftrightarrow R(x) = \dfrac{-3x^{2} + 15x}{(x - 1)(x + 2)} \geq 0$
\end{enumerate}
\end{document}
| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.