1

I would like to reproduce something like the screenshot attached here, with two separate equations in each line, each set of equations aligned amongst themselves.

On my end, LaTeX always pushes everything left of the second alignment symbol to the farthest left it can be, as if it is all part of the first equation, while I would like the left hand side of the second equation in the same line be immediately next to its own equal sign.

Specifically for the case attached here, I would like to align the two equations respectively with $\to$ and $=$ separately.

enter image description here

Also, if possible, ideally I would like to implement this with just the align environment.

Minimum not-working code:

\documentclass[11pt, oneside]{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[english]{babel}
\usepackage{amsmath}
\begin{document}
\begin{align}
\left(\begin{array}{c}{A_{\mu}} \\ {\rho_{\mu}^{*}}\end{array}\right) &\rightarrow\left(\begin{array}{cc}{\cos \theta} & {-\sin \theta} \\ {\sin \theta} & {\cos \theta}\end{array}\right)\left(\begin{array}{c}{A_{\mu}} \\ {\rho_{\mu}^{*}}\end{array}\right), \qquad\qquad\qquad\qquad\tan \theta&=\frac{g_{e l}}{g_{*}}\\
\left(\begin{array}{c}{\psi_{L}} \\ {\chi_{L}}\end{array}\right) &\rightarrow\left(\begin{array}{cc}{\cos \varphi_{\psi_{L}}} & {-\sin \varphi_{\psi_{L}}} \\ {\sin \varphi_{\psi_{L}}} & {\cos \varphi_{\psi_{L}}}\end{array}\right)\left(\begin{array}{c}{\psi_{L}} \\ {\chi_{L}}\end{array}\right), \hfill \tan \varphi_{\psi_{L}}&=\frac{\Delta}{m}\\
\left(\begin{array}{c}{\tilde{\psi}_{R}} \\ {\tilde{\chi}_{R}}\end{array}\right) &\rightarrow\left(\begin{array}{cc}{\cos \varphi_{\tilde{\psi}_{R}}} & {-\sin \varphi_{\tilde{\psi}_{R}}} \\ {\sin \varphi_{\tilde{\psi}_{R}}} & {\cos \varphi_{\tilde{\psi}_{R}}}\end{array}\right)\left(\begin{array}{c}{\tilde{\psi}_{R}} \\ {\tilde{\chi}_{R}}\end{array}\right), \quad \tan \varphi_{\tilde{\psi}_{R}}&=\frac{\tilde{\Delta}}{\tilde{m}}
\end{align}
\end{document}
  • \hfill doesnt working as you liked. You need to use some adequate math environment (array, alignat, etc). For help please provide MWE that we not need to rewrite your equations from scratch. Otherwise your question probably will be closed as "to broad". – Zarko Jul 18 at 9:45
  • @Zarko MWE added. – Rethliopuks Jul 18 at 9:51
  • 1
    sorry, this is only code fragment, not an MWE. Please extend it to complete small document. – Zarko Jul 18 at 9:52
  • @Zarko sorry, updated. Please let me know if it does not work for you. – Rethliopuks Jul 18 at 9:58
  • see my answer. it maybe provide what you looking for :-) – Zarko Jul 18 at 10:10
1

like this?

enter image description here

with use of pmatrix from asmath and extend align environment with one more ampersand:

\documentclass{article}
\usepackage{amsmath,amssymb,amsthm}

\begin{document}
\begin{align}
\begin{pmatrix}
    A_{\mu}\\ \rho_{\mu}^{*}
\end{pmatrix}
    & \rightarrow   \begin{pmatrix}
                    \cos \theta & -\sin \theta \\
                    \sin \theta &  \cos \theta
                    \end{pmatrix}\begin{pmatrix}
                                    A_{\mu} \\ \rho_{\mu}^{*}
                                 \end{pmatrix},
    &   \tan \theta & = \frac{g_{e l}}{g_{*}}         \\
\begin{pmatrix}\psi_{L} \\ \chi_{L} \end{pmatrix}
    & \rightarrow   \begin{pmatrix}
                    \cos \varphi_{\psi_{L}} & -\sin \varphi_{\psi_{L}} \\ 
                    \sin \varphi_{\psi_{L}} &  \cos \varphi_{\psi_{L}}
                    \end{pmatrix}\begin{pmatrix}
                                    \psi_{L} \\ \chi_{L}
                                 \end{pmatrix},
    &   \tan \varphi_{\psi_{L}} 
            & = \frac{\Delta}{m}    \\
\begin{pmatrix}
    \tilde{\psi}_{R} \\  \tilde{\chi}_{R}
\end{pmatrix}
    & \rightarrow   \begin{pmatrix}
                    \cos \varphi_{\tilde{\psi}_{R}} & -\sin \varphi_{\tilde{\psi}_{R}}  \\ 
                    \sin \varphi_{\tilde{\psi}_{R}} &  \cos \varphi_{\tilde{\psi}_{R}}
                    \end{pmatrix}\begin{pmatrix}
                                    \tilde{\psi}_{R} \\\tilde{\chi}_{R}
                                 \end{pmatrix},
    &   \tan \varphi_{\tilde{\psi}_{R}} 
            & =\frac{\tilde{\Delta}}{\tilde{m}}
\end{align}
\end{document}    
2

I'd propose alignat, that gives more control of spacing between the column pairs.

The second parts of each row should not, in my opinion, be aligned at the equals sign, because the prominence should be to “tan”.

\documentclass[11pt, oneside]{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage[english]{babel}
\usepackage{amsmath}
\begin{document}
\begin{alignat}{2}
\begin{pmatrix} A_{\mu} \\ \rho_{\mu}^{*} \end{pmatrix}
  & \rightarrow
    \begin{pmatrix} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{pmatrix}
    \begin{pmatrix} A_{\mu} \\ \rho_{\mu}^{*} \end{pmatrix},
  &\quad& \tan \theta = \frac{g_{e l}}{g_{*}}
\\
\begin{pmatrix} \psi_{L} \\ \chi_{L} \end{pmatrix}
  & \rightarrow
    \begin{pmatrix}
      \cos \varphi_{\psi_{L}} & -\sin \varphi_{\psi_{L}} \\
      \sin \varphi_{\psi_{L}} & \cos \varphi_{\psi_{L}}
    \end{pmatrix}
    \begin{pmatrix} \psi_{L} \\ \chi_{L} \end{pmatrix},
  && \tan \varphi_{\psi_{L}} = \frac{\Delta}{m}
\\
\begin{pmatrix} \tilde{\psi}_{R} \\ \tilde{\chi}_{R} \end{pmatrix}
   & \rightarrow
     \begin{pmatrix}
       \cos \varphi_{\tilde{\psi}_{R}} & -\sin \varphi_{\tilde{\psi}_{R}} \\
       \sin \varphi_{\tilde{\psi}_{R}} & \cos \varphi_{\tilde{\psi}_{R}}
     \end{pmatrix}
     \begin{pmatrix} \tilde{\psi}_{R} \\ \tilde{\chi}_{R} \end{pmatrix},
   && \tan \varphi_{\tilde{\psi}_{R}} = \frac{\tilde{\Delta}}{\tilde{m}}
\end{alignat}

\end{document}

enter image description here

Your opinion may differ. In any case, avoid overusing braces.

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