Is it possible to make the integral sign smaller? I found that in the Display Mode the integral sign seems automatically longer. But I am in a context where smaller integral sign would be preferred.



If you prefer to have any size of the integral sign (you can choose the size that you like), it is possible to use scalerel package with the option \scaleobj{<scale factor>}{...}.

enter image description here


\int^{b}_{a}\frac{1}{x}\,dx, \quad 
  • Thank you really much! This is what I was talking about I guess :).
    – Megadeth
    Aug 25 '19 at 5:19
  • @Megadeth I am happy for you, I am very glad to help you. Please, can you check instead Bernard's answer? Because it is better than mine for many reasons. Thank you very much.
    – Sebastiano
    Aug 25 '19 at 11:34
  • Hi, easy! I was not making a comparison. I guess my comment was just a shout of joy. I appreciate every feedback in general.
    – Megadeth
    Aug 25 '19 at 12:51
  • @Megadeth Hi, :-) my code is very generic and although you like it and there are many positive and negative aspects. I hope you change the green v to Bernard because I think it is fairer and more correct :-)
    – Sebastiano
    Aug 25 '19 at 14:26

The nccmath package provides a medium-size integral sign , with the \medint\int command. There are also medium-sized fractions (\mfrac), the more general medmath{...} command. and medsize environments. You obtain formulæ with a size of ~80 % \displaystyle, avoiding the discrepancy with \textstyle .

The following code provides a demo:

\usepackage{mathtools, nccmath}


Different kinds of integrals: 

    \int_{0}^{1}\frac{\mathrm d x}{1 + x^2} & = \frac\pi 4 %
     &\texttt{\textbackslash medint: \quad} \medint\int_{0}^{1}\frac{\mathrm d x}{1 + x^2} & = \frac\pi 4 \\[2ex]
    \begin{tabular}{ >{\ttfamily}r}
    \textbackslash medint\\ +\textbackslash mfrac\enspace\end{tabular} \quad \medint\int_{0}^{1}\mfrac{\mathrm d x}{1 + x^2} & = \mfrac\pi 4
       & \texttt{\textbackslash textstyle: }\quad\textstyle{\int_{0}^{1}}\frac{\mathrm d x}{1 + x^2} & = \frac\pi 4


enter image description here

  • Yes, that was a private conversation.
    – Bernard
    Aug 25 '19 at 11:58

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