Is it possible to make the integral sign smaller? I found that in the Display Mode the integral sign seems automatically longer. But I am in a context where smaller integral sign would be preferred.
Thanks.
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Sign up to join this communityIf you prefer to have any size of the integral sign (you can choose the size that you like), it is possible to use scalerel
package with the option \scaleobj{<scale factor>}{...}
.
\documentclass[a4paper,12pt]{article}
\usepackage{mathtools}
\usepackage{scalerel}
\begin{document}
\[
\int^{b}_{a}\frac{1}{x}\,dx, \quad
\scaleobj{.5}{\int^{b}_{a}}\frac{1}{x}\,dx,
\quad
\scaleobj{1.5}{\int^{b}_{a}}\frac{1}{x}\,dx,
\quad
\scaleobj{2}{\int^{b}_{a}}\frac{1}{x}\,dx,\quad
\scaleobj{.3}{\int^{b}_{a}}\frac{1}{x}\,dx
\]
\end{document}
The nccmath
package provides a medium-size integral sign , with the \medint\int
command. There are also medium-sized fractions (\mfrac
), the more general medmath{...}
command. and medsize
environments. You obtain formulæ with a size of ~80 % \displaystyle, avoiding the discrepancy with \textstyle
.
The following code provides a demo:
\documentclass{article}
\usepackage[utf8]{inputenc}%
\usepackage{mathtools, nccmath}
\usepackage{array}
\newcommand{\Leg}[3][]{\left(\frac{#2}{#3}\right)_{#1}}
\begin{document}
Different kinds of integrals:
\begin{align*}
\int_{0}^{1}\frac{\mathrm d x}{1 + x^2} & = \frac\pi 4 %
&\texttt{\textbackslash medint: \quad} \medint\int_{0}^{1}\frac{\mathrm d x}{1 + x^2} & = \frac\pi 4 \\[2ex]
\begin{tabular}{ >{\ttfamily}r}
\textbackslash medint\\ +\textbackslash mfrac\enspace\end{tabular} \quad \medint\int_{0}^{1}\mfrac{\mathrm d x}{1 + x^2} & = \mfrac\pi 4
& \texttt{\textbackslash textstyle: }\quad\textstyle{\int_{0}^{1}}\frac{\mathrm d x}{1 + x^2} & = \frac\pi 4
\end{align*}%
\end{document}
\textstyle
...