0

I'am having problems creating this simple combinatorial circuit with circuitikz: enter image description here

I don't know how to link the ports between them and how to put the ports in a particular position.

Can someone help me?

4
  • 1
    There are examples here. See tex.stackexchange.com/questions/386909/… for example. Sep 13 '19 at 21:49
  • @JohnKormylo thanks Sep 13 '19 at 22:01
  • You can look also at pages 88-89 of the manual, you have very similar examples. Have a try at it, and if you get stuck post what you have got and we'll try to help you going forward!
    – Rmano
    Sep 13 '19 at 22:26
  • @GerardoZinno please see if the answer below satisfies your requirement
    – js bibra
    May 4 at 1:08
0

enter image description here

\documentclass[a4paper]{article}
\usepackage[dvipsnames]{xcolor}
\usepackage[siunitx, RPvoltages]{circuitikz}
\usetikzlibrary{circuits.logic.US} % TiKZ Library for US Logic Circuits.
\usetikzlibrary{positioning, arrows.meta, calc}


\begin{document}
\begin{circuitikz}
    \ctikzset{logic ports=ieee,}
    \draw [thick]
                %placing the OR port at coordinate 0,0
                %name the OR port as (or)
                %placing a node right of the port with the label B_out  
                (0,0)                                   node [or port](or){} 
                                                        node [right=2pt of or]{\bfseries $\text{B}_{out}$}
                %placing the and port upper side relative to the (or) port
                (or)                ++(-3,2)            node [and port, scale=1.2] (andupper){}                             
                %placing the and port lower side relative to the (or) port
                (or)                ++(-3,-2)           node [and port, scale=1.2] (andlower){}                             
                %connecting and upper output with (or) input 1
                (andupper.out)      -| (or.in 1)            
                %connecting and lower output with (or) input 2  
                (andlower.out)      -| (or.in 2)
                %extending andlower input 2 to left side and label d
                (andlower.in 2)--   ++(-3,0)            node[left]{\bfseries d}
                (andlower.in 1)--   ++(-3,0)            node[left]{\bfseries c}
                (andupper.in 2)--   ++(-3,0)            node[left]{\bfseries b}     coordinate(b) 
                %placing the not port and name it (not) relative to and upper port
                (andupper.in 1)     ++(-1.5,0)          node[not port](not){}
                %connecting the not port to and upper port input
                (andupper.in 1)--   (not.out);
                %draw an imaginary path connecting not input to coordinate (b)
                %this gives the second coordinate (bb) at the downwards turning point on the imaginary path
    \path       (not.in)-|                                                          coordinate(bb)(b);
                %extending the not port input to left upto coordinate (bb) and label a
    \draw       (not.in)--          (bb)                node[left]{\bfseries a}     
                ;
    
    
\end{circuitikz}
\end{document}
0

Your scheme can be drawn also on the following way:

enter image description here

\documentclass[border=3.141592]{standalone}
\usepackage{circuitikz}
\usetikzlibrary{calc}
\ctikzset{logic ports=ieee}

\begin{document}
    \begin{circuitikz}[line cap=round,
                       font=\sffamily\bfseries]
\draw   (0,2.4) node (A) [and port] {};
\node [notcirc, left] at (A.bin 1) {};
\draw   (0,0.0) node (B) [and port] {}
        ($(A.out)!0.5!(B.out)$) node (C) [or port, right] {}
        (A.out) --  (C.in 1)
        (B.out) --  (C.in 2)
        (A.in 1) node[left] {a}
        (A.in 2) node[left] {b}
        (B.in 1) node[left] {b}
        (B.in 2) node[left] {d}
        (C.out)  node[right] {B\textsubscript{out}};
   \end{circuitikz}
\end{document}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.