When the symbol in the \sqrt
is too large, the \sqrt
rendered in the article is too vertical and is not very beautiful. I want it to have a tilt angle, just like when there are few symbols inside. what should I do?
The fact that the steepness of the surds increases with the overall size of the square-root symbols is not a flaw in the design of the math font. Instead, it embodies a long-standing typographic tradition that has held up pretty well over the decades (and probably even centuries).
If you can't stand the "vertical look" of the taller surds, do contemplate some alternatives. Among them are (a) using \tfrac
("text style frac") rather than \frac
; (b) using inline-fraction notation; (c) using reciprocal notation (e.g, 3^{-2}
rather than \frac{1}{3^2}
); and (d) parenthetic notation instead of \sqrt
-- either with automatically sized parentheses or explicitly sized parentheses.
\documentclass{article}
\usepackage{amsmath} % for 'align*' env. and '\tfrac' and '\dotsb' macros
\usepackage{newpxtext,newpxmath} % Palatino clone
\begin{document}
\begin{align*}
c_n
&= \sqrt{\frac{1}{3^2}+\sqrt{\frac{1}{4^2}+\sqrt{\dotsb+\frac{1}{n^2}}}}\\
&= \sqrt{\tfrac{1}{3^2}+\sqrt{\tfrac{1}{4^2}+\sqrt{\dotsb+\tfrac{1}{n^2}}}}\\
&= \sqrt{1/3^2+\sqrt{1/4^2+\sqrt{\dotsb+1/n^2}}}\\
&= \sqrt{3^{-2}+\sqrt{4^{-2}+\sqrt{\dotsb+\mathstrut n^{-2}}}}\\
&= \left(\frac{1}{3^2}+\left(\frac{1}{4^2}+\left(\dotsb+\frac{1}{n^2}
\right)^{\!\!-1/2\,} \right)^{\!\!-1/2\,} \right)^{\!\!-1/2}\\
&= \Biggl(\frac{1}{3^2}+\biggl(\frac{1}{4^2}+\Bigr(\dotsb+\frac{1}{n^2}
\Bigr)^{\!\!-1/2\,} \biggr)^{\!\!-1/2\,} \Biggr)^{\!\!-1/2}
\end{align*}
\end{document}
\documentclass...
to\end{document}
) showing what you did to produce your output. – Peter Wilson Sep 19 at 17:06\stretchrel
with\scalerel[3ex]
to scale the surd, with a 3ex width limit. – Steven B. Segletes Sep 19 at 20:33