Adjust backslashbox to a different arraystretch (row too high)

I have some code to define a table with a different height so that it looks better:

\begin{table}[h!]
\centering
{
\renewcommand{\arraystretch}{2.25}
\begin{tabular}{*{3}{|c}|}
\hline
\backslashbox{$V_b$}{$V_1$} & $-\dfrac{V_{\pi}}{4}$ & $\dfrac{V_{\pi}}{4}$  \\
\hline
$-\dfrac{V_{\pi}}{2}$ & max & min \\
\hline
$-\dfrac{V_{\pi}}{2}$ & min & max \\
\hline
\end{tabular}
}
\end{table}


But the result is the following:

I'd like that the diagonal line coincided with both corners. I have found many solutions for a wider cell, but nothing for a higher cell, and if I try to change the wide of the cell (with \backslashbox[width]) it is the same result. Thank you in advance.

With the help of diagbox and a combination of cellspace and \arraystretch:

\documentclass{article}
\usepackage{diagbox}
\usepackage{amsmath}
\usepackage{cellspace}
\setlength\cellspacetoplimit{6pt}
\setlength\cellspacebottomlimit{6pt}
\begin{document}

\begin{table}[h!]
\centering
\renewcommand{\arraystretch}{1.5}
\begin{tabular}{*{3}{|Sc}|}
\hline
\multicolumn{1}{|c|}{\backslashbox{$V_b$}{$V_1$}} & \multicolumn{1}{c|}{$-\dfrac{V_{\pi}}{4}$} & \multicolumn{1}{c|}{$\dfrac{V_{\pi}}{4}$}  \\
\hline
$-\dfrac{V_{\pi}}{2}$ & max & min \\
\hline
$-\dfrac{V_{\pi}}{2}$ & min & max \\
\hline
\end{tabular}
\end{table}
\end{document}

• It worked, thank you so much – Josemi Oct 9 at 21:38