2

I have some troubles with starting on a table for flow and layout. I would like to make it like this picture. Does anybody have a good idea? I have tried nothing and I am already out of ideas.

Like this

Kind regards Emil

2
  • 2
    This not seems to be a table. You should draw it as image. For example with tikz or pstricks packages.
    – Zarko
    Oct 17 '19 at 18:07
  • 1
    I agree with Zarko. No table package is capable do make this figure is an easy way. However, since it consists of very symmetric pieces, it shoul be pretty straight forward in TikZ or a drwing application like Ipe
    – Sveinung
    Oct 17 '19 at 18:34
2

Here is a way to do it, with a plain tabular environment, some multirows and pstricks, inserting five empty nodes for the outer polygon at the relevant places (either in empty cells or between rows) and constructing from them 24 other nodes for the lines.

\documentclass[svgnames, 12pt]{article}
\usepackage[utf8]{inputenc} %
\usepackage{array, multirow}
\usepackage{amsmath} 
\usepackage{pst-node, multido, auto-pst-pdf}
\newcounter{dept}
\newcommand*{\inbetween}[1]{\multirow{2}{*}[-0.2ex]{\thickspace#1}}

\begin{document}

    \psset{dotsize=2pt, linecolor=red, linejoin=1,linewidth =0.4pt}
    \setlength{\extrarowheight}{2pt}
    \[ \setcounter{dept}{0}
    \renewcommand{\arraystretch}{1.2}
    \psset{dotsize=2pt, linecolor=red, linejoin=1,linewidth =0.4pt}
    \begin{tabular}{>{\stepcounter{dept}\color{Tomato}\textbf{Dept\,%
     \Alph{dept}}}lc*{6}{>{{}\enspace\color{Tomato}\bfseries}c}}
    \noalign{\pnode[-1.5em, 0]{A}}
     &\pnode[0, 2.8ex]{B} & \inbetween{5}\\
     & & \inbetween{6} & 2 & \inbetween{6} & \\
      & & \inbetween{4} & 1 & \inbetween{3} & 2 & \inbetween{4} & \\
    & & \inbetween{4} & 4 & \inbetween{5} & 1 & \inbetween{6} & 3 \pnode[1.5em, 0.8ex]{S}\\
     & & \inbetween{2} & 5 & \inbetween{2} & 1\\
     & \pnode[-\tabcolsep, -4.8ex]{D} & \inbetween{3} & 3 \\%
     & \\
    \noalign{\pnode[-1.5em, 0ex]{C}}
     \end{tabular}
    \psset{linecolor=LightSlateGray, linewidth=1.2pt, linejoin=1,linearc =0.05}
     \pspolygon[fillstyle=solid, fillcolor=SlateGray, opacity = 0.15,linejoin=1](A)(B)(S)(D)(C)
    \multido{\n=0.142+0.143, \i=1+1}{6}{%
    \psLNode(A)(C){\n}{a\i} \psLNode(B)(D){\n}{b\i}
    \psLNode(B)(S){\n}{r\i} \psLNode(S)(D){\n}{s\i}
    \psline(a \i)(b\i)(r\i) \psline(b\i)(s\i)
    }%
    \]

\end{document} 

enter image description here

1
  • Thank you for the contribution! :)
    – Emil
    Oct 19 '19 at 18:36
1

I ended up using this code:

\usepackage{tikz}
\usetikzlibrary{shapes.geometric, arrows}


    \usetikzlibrary{shapes,arrows}
% Define block styles

\tikzstyle{decision} = [diamond, draw, fill=blue!20, 
    text width=3.3em, text badly centered, node distance=3cm, inner sep=0pt]
\tikzstyle{block} = [rectangle, draw, fill=blue!20,    text width=8em, text centered, minimum height=4em]
\tikzstyle{line} = [draw, -latex']

\begin{figure}[H]
    \centering
\begin{tikzpicture}[scale=0.90][node distance = 2cm, auto]
    % Place nodes
    \node [start] (1) {Laser cutter};
    \node [start, below of=1, node distance=1.51cm](2){Laser cutter};
    \node [start, below of=2, node distance=1.51cm](3){Laser cutter};
    \node [start, below of=3, node distance=1.51cm](4){Laser cutter};
    \node [start, below of=4, node distance=1.51cm](5){Laser cutter};
    \node [start, below of=5, node distance=1.51cm](6){Laser cutter};
    \node [start, below of=6, node distance=1.51cm](7){Laser cutter};

%% Row number 1
\node [decision, below of=1, node distance=1.5cm, yshift=0.75cm, xshift=2.42cm] (a1) {3};
\node [decision, below of=a1, node distance=1.51cm] (a2) {4};
\node [decision, below of=a2, node distance=1.51cm] (a3) {5};
\node [decision, below of=a3, node distance=1.51cm] (a4) {6};
\node [decision, below of=a4, node distance=1.51cm] (a5) {6};
\node [decision, below of=a5, node distance=1.51cm] (a6) {6};

%% Row number  2
\node [decision, below of=a1, node distance=1.5cm, yshift=0.75cm, xshift=0.75cm] (b1) {3};
\node [decision, below of=b1, node distance=1.51cm] (b2) {4};
\node [decision, below of=b2, node distance=1.51cm] (b3) {5};
\node [decision, below of=b3, node distance=1.51cm] (b4) {6};
\node [decision, below of=b4, node distance=1.51cm] (b5) {6};

%% Row number  3
\node [decision, below of=b1, node distance=1.5cm, yshift=0.75cm, xshift=.75cm] (c1) {3};
\node [decision, below of=c1, node distance=1.51cm] (c2) {4};
\node [decision, below of=c2, node distance=1.51cm] (c3) {5};
\node [decision, below of=c3, node distance=1.51cm] (c4) {6};   

%% Row number  4
\node [decision, below of=c1, node distance=1.5cm, yshift=0.75cm, xshift=.75cm] (d1) {3};
\node [decision, below of=d1, node distance=1.51cm] (d2) {4};
\node [decision, below of=d2, node distance=1.51cm] (d3) {5};

%% Row number  5
\node [decision, below of=d1, node distance=1.5cm, yshift=0.75cm, xshift=.75cm] (e1) {3};
\node [decision, below of=e1, node distance=1.51cm] (e2) {4};

%% Row number  6
\node [decision, below of=e1, node distance=1.5cm, yshift=0.75cm, xshift=.75cm] (f1) {3};




\end{tikzpicture}
\end{figure}

Picture of solution

Thanks for the help guys!

0

enter image description hereThis solution uses a little trigonometry, but allows you to adjust the angle.

\documentclass{standalone}
\usepackage{tikz}
\usepackage[utf8]{inputenc}
\begin{document}

\begin{tikzpicture}[line cap =round]

\pgfmathsetmacro\angle{30}
\pgfmathsetmacro\textLength{2}
\pgfmathsetmacro\height{0.6}

\def\lineColor{gray}
\def\textColor{red}
\def\backColor{blue!10}

\pgfmathsetmacro\numeroLinhas{7}
\pgfmathsetmacro\cte{\height^2/tan(\angle)}
\fill[\backColor] (0,0) -- ++(\textLength,0) -- ++(\numeroLinhas*\cte,0.5*\numeroLinhas*\height) -- ++(-\numeroLinhas*\cte,0.5*\numeroLinhas*\height) -- ++(-\textLength,0) -- cycle;
\draw[thick,\lineColor] (0,\numeroLinhas*\height) -- (0,0);
\foreach \x in {0,...,\numeroLinhas}{
 \draw[thick,\lineColor] (0,\x*\height) -- +(\textLength,0);
}
\foreach \x/\y in {0/{Dept. A},1/{Dept. B},2/{Dept. C},3/{Dept. D},4/{Dept. E},5/{Dept. F},6/{Dept. G}}{
 \pgfmathsetmacro\ka{(6.5-\x)*\height}
 \pgfmathsetmacro\kb{(\numeroLinhas-\x)*\height}
 \node[\textColor] at (0.5*\textLength,\ka) {\y};
 \draw[thick,\lineColor] (\textLength,\kb) -- +(\numeroLinhas*\cte-\x*\cte,-0.5*\numeroLinhas*\height+0.5*\x*\height);
 \draw[thick,\lineColor] (\textLength,\x*\height) -- +(\numeroLinhas*\cte-\x*\cte,+0.5*\numeroLinhas*\height-0.5*\x*\height);
}
\foreach \x/\y in {0/5,1/6,2/4,3/4,4/2,5/3}{
 \pgfmathsetmacro\kc{(6-\x)*\height}
 \node[\textColor] at (\textLength+\cte ,\kc) {\y};
}
\foreach \x/\y in {0/2,1/1,2/4,3/5,4/3}{
 \pgfmathsetmacro\kd{(5.5-\x)*\height}
 \node[\textColor] at (\textLength+2*\cte, \kd) {\y};
}
\foreach \x/\y in {0/6,1/3,2/5,3/2}{
 \pgfmathsetmacro\ke{(5-\x)*\height}
 \node[\textColor] at (\textLength+3*\cte ,\ke) {\y};
}
\foreach \x/\y in {0/2,1/1,2/1}{
 \pgfmathsetmacro\kf{(4.5-\x)*\height}
 \node[\textColor] at (\textLength+4*\cte ,\kf) {\y};
}
\foreach \x/\y in {0/2,1/1}{
 \pgfmathsetmacro\kg{(4-\x)*\height}
 \node[\textColor] at (\textLength+5*\cte ,\kg) {\y};
}
\node[\textColor] at (\textLength+6*\cte ,0.5*\numeroLinhas*\height) {3};
\end{tikzpicture}[![enter image description here][1]][1]
\end{document}

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