CircuiTikZ: Understanding the placement options of to[...]

Question

Following-up this answer, for the following MWE, why does to[short, name=motor1, pos=0.25] draw the motor midway and not place it at the end of the first 1/4 of the path ?

Additionally, is there an option of to[...] to control the placement of the motor instead of doing it manually as I did twice below?

\documentclass[border=5mm]{standalone}

\usepackage{circuitikz}

\begin{document}
    \begin{circuitikz}
        \draw (0,0) to[short, name=motor1, pos=0.25] ++(4,0);
        \draw (motor1) node[elmech](M1){M};

        \draw (0,-2) to[short, name=motor2] ++(4,0);
        \draw ([xshift=-1cm]motor2) node[elmech](M2){M};

        \draw (1,-4) node[elmech](motor3){M};
        \draw (0,-4) to[short] (motor3.west);
        \draw (motor3.east) to[short] (4,-4);
    \end{circuitikz}
\end{document}

Answer 1

I don't think pos is supposed to decide the placement of the component. The bipoles are drawn at the middle. Alternate way is using

    \draw (0,-2) -- ++(4,0)node[pos=0.25](motor2){};

Yes. Motor can be placed with to[Telmech]. Note that the name starts with T.

    \draw (0,-4) to[Telmech=M, name=M3] ++(4,0); 

\documentclass[border=5mm]{standalone}

\usepackage{circuitikz}

\begin{document}
    \begin{circuitikz}

        \draw (0,0) to[short, name=motor1, pos=0.25] ++(4,0);
        \draw (motor1) node[elmech](M1){M};

        \draw (0,-2) -- ++(4,0)node[pos=0.25](motor2){};
        \draw (motor2) node[elmech](M2){M};

        \draw (0,-4) to[Telmech=M, name=M3] ++(4,0) to[Telmech=M] ++(0,-3);         
        \draw (M3.east) -- ++(0,-1);

    \end{circuitikz}
\end{document}