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I am unable to modify the circuit tikz to look like the one from the picture enter image description here

  1. The voltage sources are inversed
  2. I don’t know how to add the V1 and V2 externally
  3. The resistor is missing

\documentclass{standalone}
\usepackage{circuitikz}

\begin{document} 
\begin{circuitikz}
\draw
  (0,0) node[pnp] (pnp1){$Q_2$} ++(.7,0) % add white space for label   
   (pnp1.B) -- ++(-.5,0) node[pnp, xscale=-1, anchor=B](pnp2){}  
  (pnp2.text) node[above left,inner sep=0pt] {$Q_1$}       
   (pnp1.B) |- (pnp1.C)
   (pnp2.B) |- (pnp2.C)
   (pnp1.text) node[below right,inner sep=10pt] {$N$} 
   (pnp2.text) node[below left,inner sep=10pt] {$1$} 

%     (npn1.E) -- ++(0,2) node[R, l_=$R_1$,-*]

      (pnp2.E) to [american, I , l_=$I_o$,-] ++(0,2) coordinate(a)
      (pnp1.E) to [american, I , l_=$I_o$,-] ++(0,2) coordinate(b)
     (a)-- (b) node[vcc]{$V_{cc}$}
;
\end{circuitikz}
\end{document}
3
  • use invert to invert the current sources. For drawing resistor you have to use (npn1.E) to[R] ++(0,2).
    – nidhin
    Nov 3, 2019 at 15:28
  • where should I add this invert? Nov 3, 2019 at 15:29
  • to[american,I, invert]
    – nidhin
    Nov 3, 2019 at 15:35

1 Answer 1

3
  1. Use invert to change the current or voltage source direction.

    1. V1 and V2 can be placed at required coordinates using node.

    2. Like any bipole, resistor can be placed with to[R]

See MWE.

\documentclass[margin=3mm]{standalone}
\usepackage{circuitikz}

\begin{document}
\begin{circuitikz}[american,node distance = 30pt]
\draw (0,0) node[ground]{} to[Tpnp,name=Q1] ++(0,2) to[short] ++(0,2)node(v1){} to[I,invert,l^=$i_0$] ++(0,2)node[tground]{};
\draw (3,0) node[ground]{} to[Tpnp,mirror,name=Q2] ++(0,2) to[R,a=$R$] ++(0,2)node(v2){} to[I,invert,l_=$i_0$] ++(0,2)node[tground]{};
\draw (Q1.B) |- (0,0);
\draw (Q2.B) |- (3,0);
\draw (v1) to[short] ++(1,0)node[below]{$v_1$} to[open,o-o] ++(1,0)node[below]{$v_2$} to[short] (v2);
\end{circuitikz}
\end{document}

enter image description here

1
  • Hm, off-topic: on the top I would not use ground symbol (well, this is also wrong in OP sketch) for supply voltage (usually designated as $V_{cc}$) :-) . Nice answer, +1.
    – Zarko
    Nov 3, 2019 at 15:56

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