1

I'd like to make a diagram like the one shown in the picture. I am able to write the first row using the \ce{} function, but don't know how to continue.

\ce{E + S <=>[k1][k_{-1}] & [ES] ->[k_2] P + E}

enter image description here

I'd be thankful for any help! Thanks in advance :)

4

With the help fo chemfig:

\documentclass{article}
\usepackage{chemfig}

\begin{document}

\schemestart
E + S \arrow(a--b){<=>[$k_1$][$k_{-1}$]} {[ES]} \arrow{->[$k_2$]} P + E
\arrow(@a--c){<=>[*{0}$k_3$][*{0}$k_{-3}$]}[-90,1,,] {[EI]}
\schemestop

\end{document}
| improve this answer | |
4

Using chemarrow package and several constructs it is possible to realize an image very similar that you have put.

enter image description here

%% Compile and read me!
\documentclass[a4paper,12pt]{article}
\usepackage{amsmath,amssymb}
\usepackage{chemarrow}
\usepackage{graphicx}
\begin{document}
\[\setlength{\jot}{-10pt}\begin{aligned}
     \mathrm{E}&+\mathrm{S}\autorightleftharpoons{$k_1$}{$k_{-1}$}[\mathrm{ES}]\autorightarrow{$k_2$}{}\mathrm{P}+\mathrm{E}\\
     &+\mathrm{I}\\[8pt]
     &\mkern-26mu\rotatebox[origin=c]{-90}{$\autorightleftharpoons{\rotatebox[origin=c]{90}{$k_3$}}{\rotatebox[origin=c]{90}{$k_{-3}$}}$}\\[10pt]
     &[\mathrm{EI}]
\end{aligned}
\]
\end{document}

With \scriptstyle you wll have the differents k more small.

\documentclass[a4paper,12pt]{article}
\usepackage{amsmath,amssymb}
\usepackage{chemarrow}
\usepackage{graphicx}
\begin{document}
\[\setlength{\jot}{-10pt}\begin{aligned}
     \mathrm{E}&+\mathrm{S}\autorightleftharpoons{$\scriptstyle k_1$}{$\scriptstyle k_{-1}$}[\mathrm{ES}]\autorightarrow{$\scriptstyle k_2$}{}\mathrm{P}+\mathrm{E}\\
     &+\mathrm{I}\\[8pt]
     &\mkern-20mu\rotatebox[origin=c]{-90}{$\autorightleftharpoons{\rotatebox[origin=c]{90}{$\scriptstyle k_3$}}{\rotatebox[origin=c]{90}{$\scriptstyle k_{-3}$}}$}\\[10pt]
     &[\mathrm{EI}]
\end{aligned}
\]
\end{document}

Here there is an example:

enter image description here

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