0

i have this latex code:

\documentclass{article}
\usepackage{mathtools}

\begin{document}
$\mathrm{P} 4.2$ Consider the sequence $x(n)=(0.9)^{n} \cos (\pi n / 4) u(n) .$ Let
$y(n)=\left\{\begin{array}{ll}{x(n, 2),} & {n=0, \pm 2, \pm 4, \cdots} \\ {0,} & {\text { otherwise }}\end{array}\right.$
1. The z-transform $Y^{\prime}(z)$ of $v(n)$ in terms of the $z$ -transform $X(z)$ of $x(n)$ : Consider
\[
\begin{aligned}
Y(\tau) &=\sum_{n=-\infty}^{\infty} y(n) z^{-n}=\sum_{n=-\infty}^{\infty} x(n / 2) z^{-4} ; n=0, \pm 1, \pm 2, \ldots \\
&=\sum_{n=-\infty}^{\infty} x(n) z^{-2 n}=\sum_{m=-\infty}^{\infty} x(m)\left(z^{2}\right)-X\left(z^{2}\right)
\end{aligned}
\]
2. The z-transfiorm of $r(n)$ is giver by $\begin{aligned} X(z)=&=\left\{[0.9)^{\prime \prime} \cos (\pi n ; 4)\right]=\frac{1-\left[(0.9)(05(\pi / 4)] t^{-1}\right.}{1-2(0.9) \cos (\pi / 4)]=}+(0.9)^{2} z^{-2} \\=& \frac{-11.53642^{-1}}{1-1.27280+0.81=}:|z|>0.9 \\ & r=1=\frac{1-0.6264-2}{1-1.2728 \cdot 2+0.81=-1} ; \quad \sqrt{1.9}=0.3487 \end{aligned}$

\end{document} 

like this output:

enter image description here an like to change the English text like consider to Farsi text like در نظر گرفتن so how could i do it?

i tried to do it by removing the Eng to Farsi by this kind:

\documentclass{article}
\usepackage{mathtools}
\usepackage{xepersian}
\settextfont{Titr}
\setlatintextfont{Lato Thin}

\begin{document}

$\mathrm{P} 4.2$
\textbf{در نظر گرفتن }
 the sequence $x(n)=(0.9)^{n} \cos (\pi n / 4) u(n) .$ 
$y(n)=\left\{\begin{array}{ll}{x(n, 2),} & {n=0, \pm 2, \pm 4, \cdots} \\ {0,} & {\text { otherwise }}\end{array}\right.$
1. تبدیل Z  $Y^{\prime}(z)$ of $v(n)$ in terms of the $z$ -transform $X(z)$ of $x(n)$ : Consider
\[
\begin{aligned}
Y(\tau) &=\sum_{n=-\infty}^{\infty} y(n) z^{-n}=\sum_{n=-\infty}^{\infty} x(n / 2) z^{-4} ; n=0, \pm 1, \pm 2, \ldots \\
&=\sum_{n=-\infty}^{\infty} x(n) z^{-2 n}=\sum_{m=-\infty}^{\infty} x(m)\left(z^{2}\right)-X\left(z^{2}\right)
\end{aligned}
\]
2. The z-transfiorm of $r(n)$ is giver by $\begin{aligned} X(z)=&=\left\{[0.9)^{\prime \prime} \cos (\pi n ; 4)\right]=\frac{1-\left[(0.9)(05(\pi / 4)] t^{-1}\right.}{1-2(0.9) \cos (\pi / 4)]=}+(0.9)^{2} z^{-2} \\=& \frac{-11.53642^{-1}}{1-1.27280+0.81=}:|z|>0.9 \\ & r=1=\frac{1-0.6264-2}{1-1.2728 \cdot 2+0.81=-1} ; \quad \sqrt{1.9}=0.3487 \end{aligned}$

\end{document} 

but the output don't changed correctly like this:

enter image description here

Thanks.

1

First of all, it looks like you don't have the font Lato Thin in your system. Install it first. (Or delete it and process) Second, your editor must be bidirectional; Like texstudio or biditexmaker .... Third, in the Persian text for writing English you must use the \lr{text} command.

Good luck.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.