I would like the intersection of sets P and Q to be white as in the attached figure.
My command is as follows:
\documentclass[10pt, a4paper, serif, xcolor = {divpsnames, svgnames}]{beamer}
\usepackage{amsmath, mathtools, mathrsfs, amstext, xfrac}
\usepackage[utf8]{inputenc}
\usepackage[brazil]{babel}
\usepackage{tikz}
\usepackage{pgfplots}
\begin{document}
\begin{frame}
\frametitle{}{}
\begin{figure}
\centering
\begin{tikzpicture}
\begin{scope}[fill opacity = .5, text opacity = 1]
\draw[fill = Green!70!white, even odd rule] (5, -2) rectangle (-3.5, 2) (0:2cm) circle [radius = 1];
\draw[fill = Green!70!white, draw = black, even odd rule] (0, 0) circle [radius = 1.5];
\draw[fill = white, draw = black, even odd rule] (0:2cm) circle [radius = 1];
\node at (2, 1.3) (Q) {$Q$};
\node at (0, 1.7) (P) {$P$};
\node at (4.7, 1.7) (E) {$E$};
\end{scope}
\end{tikzpicture}
\caption{Representação de $P - Q$.}
\label{fig9}
\end{figure}
\end{frame}
\end{document}
Thanks in advance!
\draw[fill = white, draw = black, even odd rule] (0, 0) circle [radius = 1.5];
for the second\draw
call (the third one may be commented out).