0

I have a problem, don't know how to put this two arrows on picture. You can see picture how need to be and where I stuck with that. Also I provide code that you can see what I done till now.Thanks for helping

image what I need

image what I have

\begin{center}
\begin{tikzpicture}
\tikzstyle{vertex}=[circle,fill=black!3]
\tikzstyle{edge}={->,thick}

\node[vertex] (v1) at (1,2) {1};
\node[vertex] (v2) at (2,0) {2};
\node[vertex] (v3) at (0,-2) at {3};

 \draw[directed] (v1) -- (v3);
\draw[directed] (v2) -- (v1);
 \draw[directed] (v3) -- (v2);



\path (v3) edge [bend left] node[] {}(v1);
\path (v2) edge [bend right] node[] {}(v1);
\draw (1,-0.3) node[bellow]{2};
\draw (0.4,1) node[right]{1};
\draw (1.3,0.8) node[above]{1};
2
  • 2
    Welcome to TeX.SX! Please make your code compilable (if possible), or at least complete it with \documentclass{...}, the required \usepackage's, \begin{document}, and \end{document}. That may seem tedious to you, but think of the extra work it represents for TeX.SX users willing to give you a hand. Help them help you: remove that one hurdle between you and a solution to your problem. – Rmano May 27 '20 at 16:44
  • 1
    thanks to notice that, this is my first question, I will fix it now – kileuskas May 27 '20 at 16:49
0

Here is a way.

\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{decorations.markings,quotes}
\tikzset{->-/.style={decoration={% https://tex.stackexchange.com/a/39282/194703
  markings,
  mark=at position #1 with {\arrow{>}}},postaction={decorate}},
  ->-/.default=0.55}
\begin{document}
\begin{tikzpicture}[vertex/.style={circle,fill=black!3},>=stealth,auto,
    directed/.style={->-,thick}]
 \path foreach \X in {1,2,3} 
 { (210-120*\X:2) node[vertex](v\X){$\mathsf{\X}$} };
 \path[every edge/.append style={directed},bend angle=15] 
 (v3) edge[bend left,"$1$"] (v1)  edge["$1$"'] (v2)
 (v2) edge[bend right,"$1$"'] (v1)
 (v1) edge[bend left,"$1$"] (v3)
 (v1) edge[bend right,"$1$"'] (v2);
\end{tikzpicture}
\end{document}

enter image description here

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.