I used $GL(V)=: \{V\in \mathbb{C}^n : \exists W\in \mathbb{C}^n, VW = WV = 1\}$, which is to express
as highlighted.
But it sounds having errors, although it can compile. But I want to know is there anything that I can make it better.
Thank you!
I add my proposal using simply \mathsf{GL} (sans-serif font) for GL.
\documentclass[a4paper,12pt]{article}
\usepackage{mathtools,amssymb}
\begin{document}
$\mathsf{GL}(\mathrm{V})\eqqcolon\{\mathrm{V}\in \mathbb{C}^n \colon \exists \mathrm{W}\in \mathbb{C}^n, \mathrm{VW} = \mathrm{WV} = 1\}$
\end{document}
-
1If you choose to render
Vin upright lettering toward the end of the formula, you should probably give it the same typographic treatment inGL(V). – Mico Sep 16 '20 at 19:30 -
1
You wrote,
I want to know is there anything that I can [do to] make it better
If the GL term is an operator, it's best to typeset it using upright roman letters. Separately, I think the overall look would improve if slightly greater visual prominence were given to the curly braces, e.g., by making them \big.
\documentclass{article}
\usepackage{amssymb} % for '\mathbb' macro
\usepackage{amsmath} % for '\DeclareMathOperator' macro
\DeclareMathOperator{\GL}{GL}
\usepackage{mathtools} % for '\eqqcolon' macro
\begin{document}
\[
\GL(V) \eqqcolon \bigl\{ V\in \mathbb{C}^n : \exists W\in \mathbb{C}^n, VW = WV = 1 \bigr\}
\]
\end{document}
$...$or\(...\)block. – Davislor Sep 6 '20 at 17:25GL(V)is the product of a variable G and a function L, or a function named GL. In the latter case, you might want to format it differently, e.g.\DeclareMathOperator{\GL}{GL}or\newcommand{\GL}{\mathop{\textnormal{\slshape GL}}}. – Davislor Sep 6 '20 at 17:36