-1

I want to draw the following parallelepiped but I don't have idea. Can anybody help me?

enter image description here

2

Preamble: You need to use tikz package. place is going to be the style for the corner points.

\documentclass[tikz,border=5mm]{standalone}
\usepackage{tikz}
\tikzstyle{place}=[circle,draw=black,fill=black,inner sep=0.7, outer sep=0]

The following new commands are just for easy calculations.

\begin{document}
\newcommand{\Depth}{5}
\newcommand{\Height}{4}
\newcommand{\Width}{6}
\newcommand{\Skew}{1}

Specify coordinates:

\begin{tikzpicture}[scale=1]

    \coordinate (a) at (0,0,0);
    \coordinate (b) at (\Width,0,0);
    \coordinate (c) at (\Width + \Skew,\Height,\Skew);
    \coordinate (d) at (\Skew,\Height,\Skew);
    \coordinate (e) at (0,0,\Depth);
    \coordinate (f) at (\Width,0,\Depth);
    \coordinate (g) at (\Width + \Skew,\Height,\Depth + \Skew);
    \coordinate (h) at (\Skew,\Height,\Depth + \Skew);

Draw the faces of the parallelopiped:

    \draw[fill=blue!30,opacity=0.6] (a) -- (b) -- (c) -- (d) -- (a);
    \draw[fill=blue!30,opacity=0.6] (a) -- (e) -- (f) -- (b) -- (a);
    \draw[fill=blue!30,opacity=0.6] (a) -- (d) -- (h) -- (e) -- (a);
    \draw[fill=blue!30,opacity=0.6] (d) -- (c) -- (g) -- (h) -- (d);
    \draw[fill=blue!30,opacity=0.6] (e) -- (f) -- (g) -- (h) -- (e);
    \draw[fill=blue!30,opacity=0.6] (b) -- (c) -- (g) -- (f) -- (b);

Draw the nodes and label them:

    \node[place, label=below right:{(4,2,1)}] at (a) {};
    \node[place, label=right:{(1,7,1)}] at (b) {};
    \node[place, label=above:{(2,9,7)}] at (c) {};
    \node[place, label=above:{(5,4,7)}] at (d) {};
    \node[place, label=below:{(8,1,0)}] at (e) {};
    \node[place, label=below:{(5,6,0)}] at (f) {};
    \node[place, label=above left:{(6,8,6)}] at (g) {};
    \node[place, label=left:{(9,3,6)}]  at (h) {};

\end{tikzpicture}

\end{document}

enter image description here

    \coordinate (a) at (4,2,1);
    \coordinate (b) at (1,7,1);
    \coordinate (c) at (2,9,7);
    \coordinate (d) at (5,4,7);
    \coordinate (e) at (8,1,0);
    \coordinate (f) at (5,6,0);
    \coordinate (g) at (6,8,6);
    \coordinate (h) at (9,3,6);

You could use the actual coordinates as well. However, this does not look the same at all, though this is technically correct representation. Actual Coordinates

1

There must be hundreds of similar pictures. Define basis vectors, draw the planes, and label the corners. The last task can be made a bit more systematic by playing with arrays.

\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{3d}
\begin{document}
\begin{tikzpicture}
 \path (3,0) coordinate (ex) (80:3) coordinate (ey) (40:2.2) coordinate (ez);
 \begin{scope}[x={(ex)},y={(ey)},z={(ez)}]
  \foreach \X in {0,1}
  {\draw[fill=blue,fill opacity=0.1,canvas is xy plane at z=\X] (0,0) rectangle (1,1);
   \draw[fill=blue,fill opacity=0.15,canvas is yz plane at x=\X] (0,0) rectangle (1,1);
   \draw[fill=blue,fill opacity=0.2,canvas is xz plane at y=\X] (0,0) rectangle (1,1);
  }
  \edef\vecO{8,1,0}
  \edef\vecX{-3,5,0}
  \edef\vecY{1,2,6}
  \edef\vecZ{-4,1,1}
  \foreach \X in {0,1}{
    \foreach \Y in {0,1}{
        \foreach \Z in {0,1}{
            \pgfmathtruncatemacro{\myx}{{\vecO}[0]+\X*{\vecX}[0]+\Y*{\vecY}[0]+\Z*{\vecZ}[0]}
            \pgfmathtruncatemacro{\myy}{{\vecO}[1]+\X*{\vecX}[1]+\Y*{\vecY}[1]+\Z*{\vecZ}[1]}
            \pgfmathtruncatemacro{\myz}{{\vecO}[2]+\X*{\vecX}[2]+\Y*{\vecY}[2]+\Z*{\vecZ}[2]}
            \path (\X,\Y,\Z) 
            \ifnum\Y=0
                node[circle,fill,inner sep=1.5pt,label=below:{$(\myx,\myy,\myz)$}]{}
            \else
                node[circle,fill,inner sep=1.5pt,label=above:{$(\myx,\myy,\myz)$}]{}
            \fi;
         }}}
 \end{scope}
\end{tikzpicture}
\end{document}

enter image description here

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