I'm not sure if I may plot the contour by the use of polar plotting. I tried the following code, but there is an error that I could not fix. The rectangular part is of no matter. Just the path itself is important.

  \draw[thick,->,>=latex] (-2,0)--(2.5,0);
  \draw[thick,->,>=latex] (0,-2)--(0,2);
  \draw[thick,samples=500] plot [smooth, variable=\t, domain=0:pi] ({\t*exp(-\t r)});

enter image description here

  • Is this in polar coordinates, or rectangular? – Teepeemm Feb 23 at 14:27

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