x^\lambda_p = \begin{dcases*}
        1  & if \lambda  is assigned to P\\
        0  & $Otherwise$
  • 3
    Next time, maybe try to think of a more descriptive question title :). Mar 28 at 22:24

Be sure to use $ in the right places (but not in the wrong places):

 x^\lambda_p = \begin{dcases*}
        1  & if $\lambda$ is assigned to $p$ \\
        0  & otherwise


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A general tip: if words are set in italics and spaces are being ignored, chances are you're in math mode when you don't want to be.

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