Drawing NOT-OR gate in LaTeX

Question

I want to modify this circuit by aligning the inputs x_3, x_1 and x_2 on the same vertical line and placing the left black disc on the intersection of x_1 and the and gate.

    \begin{circuitikz}
            \node[and port] (A) at (0, 0) {};
            \node at (A) [ocirc,fill=black] {};
            \node[left] at (A.in 1) {\(x_1\)};
            \node[left] at (A.in 2) {\(x_2\)};
            
            \node at (A.bin 1) [ocirc,fill=black] {};
            \node[or port] (B) at (2.7,-0.28) {};
            \node (in3) at ($(B.in 2) - (3, 0)$) {};
            \draw (in3) -- (B.in 2);
            \node at (in3)  {\(x_3\)};
            \node[right] at (B.out) {\((x_1'x_2)'+x_3\)};
            
            \draw (A.out)  --  (B.in 1);
        \end{circuitikz}

This produces this

But I want this

How do I also make the inverter symbol a black disc instead of a circle?

Answer 1

Maybe this? But you may be more specific about what you need.

\documentclass{article}
\usepackage{circuitikz}
\begin{document}

\begin{circuitikz}
        \node[and port, number inputs=1] (A) at (0, 0) {};
        \node at (A) [ocirc,fill=black] {};
        \node[left] at (A.in 1) {\(x_1\)};
        \node[left] at (A.in 2) {\(x_2\)};
        
        \node[or port] (B) at (4,0.28) {};
        \node[left] at (B.in 1) {\(x_3\)};
        \node[right] at (B.out) {\((x_1'x_2)'+x_3\)};
        
        \draw (A.out)  --  (B.in 2);
    \end{circuitikz}

\end{document}

EDIT

So maybe this one?

\documentclass{article}
\usepackage{circuitikz}
\begin{document}

\begin{circuitikz}
        \node[and port, number inputs=1] (A) at (0, 0) {};
        \node at (A) [ocirc,fill=black] {};
        \node[left] at (A.in 1) {\(x_1\)};
        \node at (A.left) [yshift=8pt,ocirc,fill=black] {};
        \node[left] at (A.in 2) {\(x_2\)};
        
        \node[or port] (B) at (3,-.65) {};
        \node[left] at (B.in 2-| A.in 1) (x3) {\(x_3\)};
        \node[right] at (B.out) {\((x_1'x_2)'+x_3\)};
        
        \draw (A.out)  --++ (1,0) |-  (B.in 1);
        \draw (x3)  --  (B.in 2);
    \end{circuitikz}

\end{document}

SECOND EDIT

Following OP's demand, I propose another evolution of the solution, but it's now mandatory to scale the OR gate a bit.

\documentclass{article}
\usepackage{circuitikz}
\begin{document}

\begin{circuitikz}
        \node[and port, number inputs=1] (A) at (0, 0) {};
        \node at (A) [ocirc,fill=black] {};
        \node[left] at (A.in 1) {\(x_1\)};
        \node at (A.in 1) [xshift=6.5pt,ocirc,fill=black] {};
        \node at (A.left) [yshift=8pt,ocirc,fill=black] {};
        \node[left] at (A.in 2) {\(x_2\)};
        
        \node[or port,scale=1.2] (B) at (3,-.35) {};
        \node[left] at (B.in 2-| A.in 1) (x3) {\(x_3\)};
        \node[right] at (B.out) {\((x_1'x_2)'+x_3\)};
        
        \draw (A.out)  -- (B.in 1);
        \draw (x3)  --  (B.in 2);
    \end{circuitikz}

\end{document}