I am using \pst@divide to divide a length in half

\addlength{\DIST}{\RLEN} % does not work. 

the problem is that \pst@divide returns a float and I need it to be a length because later I add another length to the result using \addlength. Any suggestion how to covert from a float to a length or maybe how to add two float values.

  • "does not work" does not work for me. Please post the actual error message. Normally you simply need to add a unit (pt) if non is included. Jun 14 '12 at 19:30
  • "does not work" means that it has the value 0
    – Inquirer
    Jun 14 '12 at 19:38
  • That's the problem with "does not work". It can man 1.000 different things. Jun 14 '12 at 19:40
  • Sorry, I shall keep that in mind next time :)
    – Inquirer
    Jun 14 '12 at 19:41

use the etex extension \dimexpr:

\newlength\OFFSET \OFFSET=1cm




However, you can always use \addtolength\DIST{\XX pt} if \XX is not a length

  • Thanks! That's a much more simpler way for me to do these distance calculations :)
    – Inquirer
    Jun 14 '12 at 19:18

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