6

I'm trying to draw a diagram but I get the following error message:

! Xy-pic error: in entry "1,1": No [ld] (is "2,0") from here.

The code is:

\xymatrix{A\times B \ar[ld]_p \ar[rd]_q\\
          &A &B}

With the code

\xymatrix{& C \ar@/_/[ld]_f \ar[d]_{(f,g)} \ar@/^/[rd]^g\\
          & A\times B \ar[ld]_p \ar[rd]^q\\
          A && B}

here's the error I got:

! Xy-pic error: in entry "1,2": No [rd] (is "2,3") from here.

  • 2
    If you want a triangle, then add & before the first A; the second row should be A && B. In your code the first arrow wants to go left, but you're in the leftmost column, so the error. This should be thought of as a three column matrix. – egreg Jun 19 '12 at 14:13
  • Oh, I see. Why do I need two && on the second row? – justow Jun 19 '12 at 14:17
  • I don't really understand the error messages from xypic. They are not really helpful for someone who has just started using the package. – justow Jun 19 '12 at 14:44
  • 1
    If the bent arrows from C should point to A and B, there should be [ldd] and [rdd]: you want to go down two rows. Wouldn't it be better to add this to the other very similar question? – egreg Jun 19 '12 at 14:44
  • Oh, right, forgot that I actually have 3 rows as well. I'm not sure how to move this question to the previous one I posted. Feel free to move it if you want. Thanks egreg! – justow Jun 19 '12 at 14:50
8

Let's see the triangle as a two row, three column matrix:

* & A \times B & * 

A &      *     & B

where * denotes an empty cell. Now it's easy to complete it with arrows:

\xymatrix{
  & A\times B \ar[ld]_{p} \ar[rd]^{q} \\
  A && B
}

You may want to reduce the distance between columns with something like

\xymatrix@C-6pt{
  & A\times B \ar[ld]_{p} \ar[rd]^{q} \\
  A && B
}

For the second diagram you have to go down by two rows from the "C" node:

\xymatrix{& C \ar@/_/[ldd]_f \ar[d]_{(f,g)} \ar@/^/[rdd]^g\\
          & A\times B \ar[ld]_p \ar[rd]^q\\
          A && B}

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