I have a trouble with this code:


I'd like to get an Arch-Arrow of the same type of \ar@2{<->}[r] that bonds \boxed{1.} to \boxed{5.}. How Must I do? Please Help Me, Thank you so much!

  • It would be easier to help if your example is compilable. Please extend it to start with \documentclass and end with \end{document}. Jul 22, 2021 at 19:32

1 Answer 1


Bend and shift the arrow.



  \fbox{1.} \ar@2{<->}[r] &
  \fbox{2.} \ar@2{<->}[r] &
  \fbox{3.} \ar@2{<->}[r] &
  \fbox{4.} \ar@2{<->}[r] &
  \fbox{5.} \ar@2 @<-0.5ex> @/_1.5pc/ @{<->}[llll]


enter image description here

Note that, semantically, \fbox is better than \boxed. On the other hand, while the bent arrow might be good when explaining on the blackboard, I feel it useless on a printed document.

  • 1
    Thank you so much. I'm writing a Treatise of ALGEBRA. Thx again
    – Puck
    Jul 22, 2021 at 22:39

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