# remove big space between equations in split environment

I am new to latex and struggling to remove big space between the equations and between equation and text. I am using \documentclass{extarticle} and the equations I am writing are big which looks like

\begin{equation}

\begin{split}

Long equations taking more than half page

\end{split}

\end{equation}


I think that latex is taking all the equations as one piece and that's why when half page is left, the equations are shifted to next page. (I am using split command, because it aligns the equations easily using '&') Please tell me how to get rid of this problem.

The actual code is

 \section{Diffeomorphism}
$L_o = m(\dot{x}^2)^\frac{1}{2}$\10pt] \dot{x}^2 = \dot{x_\mu}\dot{x^\mu} = \dot{x_0}\dot{x^0}+\dot{x_1}\dot{x^1}+.....................+\dot{x_{D-1}}\dot{x^{D-1}}\\[15pt] Action S = \int_{-\infty}^{\infty} d\tau \; m(\dot{x}^2)^\frac{1}{2}\\[10pt] Diffeomorphism\\ \tau \rightarrow \tau' = f(\tau) \simeq \tau -\epsilon(\tau)\\ f(\tau) = finite\; at\; \tau =0\\ f(\tau) \rightarrow 0 as \tau \rightarrow \pm \infty\\ Action remains invariant under Diffeomorphism Transformations. We can prove it as follows:\\ \begin{equation} \begin{split} S' & = \int_{-\infty}^{\infty} d\tau' \; m\left[\left(\frac{dx^\mu}{d\tau'}\right)\left(\frac{dx_\mu}{d\tau'}\right)\right]^\frac{1}{2}\\[10pt] &=\int_{-\infty}^{\infty} \frac{d\tau'}{d\tau}d\tau \; m\left[\left(\frac{dx^\mu}{d\tau}\right)\left(\frac{d\tau}{d\tau'}\right)\left(\frac{dx_\mu}{d\tau}\right)\left(\frac{d\tau}{d\tau'}\right)\right]^\frac{1}{2}\\[10pt] &=\int_{-\infty}^{\infty} d\tau \left(\frac{d\tau'}{d\tau}\right)\left(\frac{d\tau}{d\tau'}\right) \; m\left[\left(\frac{dx^\mu}{d\tau}\right)\left(\frac{dx_\mu}{d\tau}\right)\right]^\frac{1}{2}\\[10pt] &= \int_{-\infty}^{\infty} d\tau \; m(\dot{x}^2)^\frac{1}{2}\\[10pt] &=S \end{split} \end{equation}  The output is • I don't think that split can be broken across pages. You might try with align (requires several \notag commands, though) and \displaybreak at the appropriate spot. Jul 27, 2021 at 17:43 • Hi @sawan kt, are you breaking lines with \\ ? It hangs on your equations, but other environments such as align-family, array-family might be useful. – FHZ Jul 27, 2021 at 17:43 • yes inside align I am using \\ to break lines @FHZ Jul 27, 2021 at 17:45 • if you provide an example then people wil be able to give specific help, without an example it is harder, although if you use align rather than equation and split then the display can have a page break as egreg says Jul 27, 2021 at 17:47 • you can highlight the code and use the {} button in the editor, which marks a code section by indenting or put  before and after Jul 27, 2021 at 17:51 ## 2 Answers Short answer, no, you can't break an equation inside an split environment. One you can use is align. Try using the allowdisplaybreaks command. \begingroup \allowdisplaybreaks \begin{align} .... \end{align} \endgroup  I hope it helps • Yes, this worked. Thankyou very much. Jul 28, 2021 at 2:03 I don't know if I have given to you a good answer and I have followed your request but I have written everything on one page. Here I add my MWE example with some additional packages like parskip to justify the text and I have improved some commands. \documentclass{extarticle} \usepackage{mathtools,amssymb} \usepackage{parskip} \begin{document} \section{Diffeomorphism} L_0 = m(\dot{x}^2)^\frac{1}{2}. \vskip2pt \[\dot{x}^2 = \dot{x_\mu}\dot{x}^\mu = \dot{x_0}\dot{x}^0+\dot{x_1}\dot{x}^1+\cdots\cdots\cdots+\dot{x}_{D-1}\dot{x}^{D-1}.
\vskip2pt
\textbf{Action} $S = \displaystyle \int_{-\infty}^{\infty} d\tau \; m(\dot{x}^2)^\frac{1}{2}$.
\vskip2pt
\textbf{Diffeomorphism}
$\tau \rightarrow \tau' = f(\tau) \simeq \tau -\epsilon(\tau)$.

$f(\tau) =\text{ finite at }\tau =0$.

$f(\tau) \rightarrow 0$ as $\tau \rightarrow \pm \infty$.

Action remains invariant under \textsl{Diffeomorphism Transformations}. We can prove it as follows:
\vspace{-.2cm}
\begin{equation}
\begin{split}
S' & = \int_{-\infty}^{\infty} d\tau' \; m\left[\left(\frac{dx^\mu}{d\tau'}\right)\left(\frac{dx_\mu}{d\tau'}\right)\right]^\frac{1}{2}\\
&=\int_{-\infty}^{\infty} \left(\frac{d\tau'}{d\tau}\right) d\tau \; m\left[\left(\frac{dx^\mu}{d\tau}\right)\left(\frac{d\tau}{d\tau'}\right)\left(\frac{dx_\mu}{d\tau}\right)\left(\frac{d\tau}{d\tau'}\right)\right]^\frac{1}{2}\\
&=\int_{-\infty}^{\infty} d\tau \left(\frac{d\tau'}{d\tau}\right)\left(\frac{d\tau}{d\tau'}\right) \; m\left[\left(\frac{dx^\mu}{d\tau}\right)\left(\frac{dx_\mu}{d\tau}\right)\right]^\frac{1}{2}\\
&= \int_{-\infty}^{\infty} d\tau \; m(\dot{x}^2)^\frac{1}{2}\\
&=S
\end{split}
\end{equation}
\end{document}
` • Yes, this really helped. Thankyou Jul 28, 2021 at 2:02