I have an IEEEtran document class. I want to put a simple definition inside the document:

blab bla

I am getting the error below:

Environment definition undefined. \begin{definition}

  • The class defines no theorem-like environment. Use \newtheorem. – egreg Jun 26 '12 at 15:14

IEEEtran defines its own environments which is used to replace existing ones (like enumerate, itemize, etc.). However, it doesn't define any definition environment. You can do so by using \newtheorem:

enter image description here

\documentclass{IEEEtran}% http://www.ctan.org/pkg/ieeetran
Here is a definition.
  • 1
    I prefer to the \theoremstyle{break} in the package ntheorem. However, if I use this in IEEEtran, its theorem/definition numbers are prefixed by the Roman section number (II.5) instead of original Arabic number (2.5). How can I get both 2.5 and the break style? – hengxin Oct 10 '13 at 13:20
  • @hengxin: I assume your sections are also enumerated in Roman numerals. You can change the section numbering to be Arabic via \renewcommand{\thesection}{\arabic{section}}, or you can just have Arabic section numbering in the theorems via \renewcommand{\thetheorem}{\arabic{section}.\arabic{theorem}}. Then your numbering will be inconsistent though. Does this work? – Werner Oct 10 '13 at 14:12
  • I tried \usepackage[thmmarks]{ntheorem} \theoremstyle{break} \newtheorem{theorem}{Theorem}[section] \renewcommand{\thetheorem}{\arabic{section}.\arabic{theorem}} in IEEEtran and I got only the number "1.0": (1) Roman section numbering (2) no the keyword "Theorem"; (3) counting goes from 0 instead of 1; (4) no break style. Did I make mistakes? BTW, I decided to follow IEEEtran's default environment: (1) Roman section numbering (2) Arabic.Ababic theorem numbering (3) no break style. Thank you all the same. – hengxin Oct 11 '13 at 1:54
  • hum, I still prefer to the following theorem environment in IEEEtrans: (1) Roman section numbering (2) with keywords "Theorem"/"Definition" in bold (3) no indent of the keywords (4) Arabic.Arabic theorem numbering (5) with break style (6) counting goes from 1 within each section. So, I am demanding too much. Thanks a lot. – hengxin Oct 11 '13 at 3:37
  • 1
    @hengxin: I suggest asking a follow-up question. – Werner Oct 27 '13 at 6:29

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