# Correctly left align a set of statements with just one text

I start with this. You see that we have a few equations that all are refereed to just one number that is $(1)$ put exactly in the middle. Here, I want to put a text instead of that number and so I did the following MWF by manipulating the codes:

\documentclass[12pt]{book}
\usepackage{amsmath,amssymb,amsthm,amsfonts}
\begin{document}
\begin{flalign*}
(a)~ &  \det (A_1+A', A_2)=\det (A_1,A_2)+\det (A'_1,A_2) &\\
(b)~ &  \det(A_1, A_2+A'_2)=\det (A_1,A_2)+\det (A_1, A'_2) \\[-1.8ex]
& \hspace*{9.5cm}\text{(666)}\\[-1.8ex]
(c)~ &  \det (cA_1,A_2)=c\det (A_1,A_2) \\
(d)~& \det(A_1, cA_2)=c\det (A_1, A_2)
\end{flalign*}
\end{document}

to find:

Is there another way for that? Please guide me if this question is a duplicate and feel free to add needed tags.

Thanks for your every seconds.

## 4 Answers

A solution with minimal changes:

\documentclass[12pt]{book}
\usepackage{amsmath,amssymb,amsthm,amsfonts}
\begin{document}

$$\tag{Damien 666} \begin{array}{ll} \text{(a)}~ & \det (A_1+A', A_2)=\det (A_1,A_2)+\det (A'_1,A_2) \\ \text{(b)}~ & \det(A_1, A_2+A'_2)=\det (A_1,A_2)+\det (A_1, A'_2) \\ \text{(c)}~ & \det (cA_1,A_2)=c\det (A_1,A_2) \\ \text{(d)}~& \det(A_1, cA_2)=c\det (A_1, A_2) \end{array}$$
\end{document}

• Thanks for your time. Sep 8 at 7:25

If you compile this:

\documentclass[12pt]{book}
\usepackage{amsmath,amssymb,amsthm,amsfonts}
\begin{document}
\begin{aligned} (a)~ & \det (A_1+A', A_2)=\det (A_1,A_2)+\det (A'_1,A_2) \\ (b)~ & \det(A_1, A_2+A'_2)=\det (A_1,A_2)+\det (A_1, A'_2) \\ (c)~ & \det (cA_1,A_2)=c\det (A_1,A_2) \\ (d)~& \det(A_1, cA_2)=c\det (A_1, A_2) \end{aligned} \tag{666}
\end{document}

then you will get this:

• Thanks Jose but, I preferred the statements get left. Sep 8 at 7:25

Here's a solution that embeds an enumerate environment in a minipage environment. This approach will let you cross-reference the enumerated items via the standard \label-\ref mechanism.

\documentclass[12pt]{book}
\usepackage{enumitem}
\usepackage{amsmath} % for '\tag' macro

\begin{document}
$$\begin{minipage}{0.9\textwidth} \begin{enumerate}[label=(\alph*),left=0pt,itemsep=2pt] \item \det(A_1+A', A_2)=\det (A_1,A_2)+\det (A'_1,A_2) \item \det(A_1, A_2+A'_2)=\det (A_1,A_2)+\det (A_1, A'_2) \item \det(cA_1,A_2)=c\det (A_1,A_2) \item \det(A_1, cA_2)=c\det (A_1, A_2) \end{enumerate} \end{minipage} \tag{666}$$
\end{document}
• Thank you for the new way! It opens my eyes to see the codes better! :) Sep 10 at 16:52

You can do like that, but I'd prefer subequations.

\documentclass[12pt]{book}
\usepackage{amsmath,amssymb,amsthm,amsfonts}

\usepackage{lipsum} % for context

\begin{document}

\setcounter{equation}{665}

\lipsum[10][1-5]
\begin{flalign}
\makebox[2em][l]{(a)} & \det (A_1+A', A_2)=\det (A_1,A_2)+\det (A'_1,A_2) & \notag \\
\makebox[2em][l]{(b)} & \det(A_1, A_2+A'_2)=\det (A_1,A_2)+\det (A_1, A'_2) \notag \\[-1.8ex]
\\[-1.8ex]
\makebox[2em][l]{(c)} & \det (cA_1,A_2)=c\det (A_1,A_2) \notag \\
\makebox[2em][l]{(d)} & \det(A_1, cA_2)=c\det (A_1, A_2) \notag
\end{flalign}
\lipsum[10][1-5]

\begin{subequations}
\lipsum[10][1-5]
\begin{align}
& \det (A_1+A', A_2)=\det (A_1,A_2)+\det (A'_1,A_2)\\
& \det(A_1, A_2+A'_2)=\det (A_1,A_2)+\det (A_1, A'_2) \\
& \det (cA_1,A_2)=c\det (A_1,A_2) \\
& \det(A_1, cA_2)=c\det (A_1, A_2)
\end{align}
\lipsum[10][1-5]
\end{subequations}

\end{document}

• Thank you very much! :) Sep 10 at 16:51