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I'm having trouble drawing the Isocyanurate molecule. The link between nitrogen (N) and carbon (C) on the right side does not link correctly, as per the code - it moves a little inbound to the carbon (C).

Thank you!

\schemestart 
\chemfig{R-N=C=O + 2 R-N=C=O} \arrow \\ \chemfig{C(=[3]O)(-[1]N(-[2]R)(-[7]C=[1]O))-[6]N(-[5]R)(-[7]C(=[6]O)(-[1]N([2]-)(-[7]R)))} (Isocianurato)
\schemestop

enter image description here

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  • \chemfig{*6(N(-R)-C(=[6]O)-N(-[7]R)-C(=[1]O)-N(-R)-C(=[3]O)-)} Oct 6, 2021 at 12:48

1 Answer 1

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\documentclass[border=4pt]{standalone}
\usepackage{chemfig}
\begin{document}
\schemestart 
\chemfig{R-N=C=O}
\+ 2
\chemfig{R-N=C=O}
\arrow
\chemfig{N*6((-R)-C(=O)-N(-R)-C(=O)-N(-R)-C(=O)-)}
\arrow{0}[,0.2]
(Isocianurato)
\schemestop
\end{document}

enter image description here

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  • 1
    What was the error of the OP's code, can you add it? :) Oct 6, 2021 at 13:15
  • 1
    @VScode_fanboy The atoms C and N must be linked with a hook. \chemfig{C(=[3]O)(-[1]N(-[2]R)(-[7]C?=[1]O))-[6]N(-[5]R)(-[7]C(=[6]O)(-[1]N?(-[7]R)))}
    – polyn
    Oct 6, 2021 at 14:26

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