This is a possibility. All is pretty straightforward except for the blue lines. For them I used the calc
library to previously compute some coordinates (rotating a scope
).
This is my code:
\documentclass[tikz,border=5mm]{standalone}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}[line cap=round,line join=round,thick,rotate=30]
\draw[line width=1mm,fill=gray!15] (0,0) circle (5);
\draw[red,fill=white] (-1.5:4) foreach\i in {0,10,...,350} {arc (\i-1.5:\i+1.5:4) -- (\i+1.5:3.5) arc (\i+1.5:\i+8.5:3.5) -- (\i+8.5:4)};
\foreach\i in {1,2,...,6}
{
\begin{scope}[rotate=60*\i-60]
\coordinate (A\i) at (-10:2.5);
\coordinate (B\i) at ($(A\i)+(0.4,0)$);
\coordinate (C\i) at ($(A\i)+(0.4,-0.2)$);
\coordinate (D\i) at ($(A\i)+(0.6,-0.2)$);
\coordinate (H\i) at (10:2.5);
\coordinate (G\i) at ($(H\i)+(0.4,0)$);
\coordinate (F\i) at ($(H\i)+(0.4,0.2)$);
\coordinate (E\i) at ($(H\i)+(0.6,0.2)$);
\end{scope}
}
\draw[blue,fill=blue!20] (A1) \foreach\i in {1,...,6}
{-- (B\i) -- (C\i) -- (D\i) to[out=60*\i+10,in=60*\i+230]
(E\i) -- (F\i) -- (G\i) -- (H\i) arc (60*\i-50:60*\i-10:2.5)};
\draw[fill=white] (0,0) circle (1.5);
\end{tikzpicture}
\end{document}
And the picture:

Edit 1: And these are the coordinates I'm using.

Edit 2: A little bit explanation of some syntax. Let's take a look at the line
\draw[red,fill=white] (-1.5:4) foreach\i in {0,10,...,350} {arc (\i-1.5:\i+1.5:4) ...};
This will draw a complex path starting at the point (-1.5:4)
, that is, a point which polar coordinates are radius 4 (4 cm from the origin) and angle -1.5 (1.5 degrees from the x-axis, clockwise). Then it will repeat the code inside the curly brackets six times, substituting \i
for the values 0,60,120,180,240,300
. For example, the first iteration will be for \i=0
, so
\draw[red,fill=white] (-1.5:4) arc (0-1.5:0+1.5:4) ...;
So the first part of the complex path will be an arc
starting at the point (-1.5:4)
with an initial angle of -1.5 degrees, a final angle of 1.5 degrees and a radius of 4 cm. In this case all the angles are centered at the origin, but for more information about the center of the arcs this post could be helpful: How is arc defined in TikZ?
cm
to the radius in arc.