This is a follow up question: How do I draw it exactly as in the blackboard picture I provide, that is with ellipses around the nodes and for the bottom one with the connections to the rightmost node straight not curved.
I posted it as a comment first but I am not sure people notice when comments are added. Thanks a lot.
Edit: here is minimal working example
\documentclass[12pt]{amsbook}
\usepackage{dynkin-diagrams}
\begin{document}
Question: how do I produced a diagram which only keeps the square in this diagram
\dynkin[fold] A{*****}? I.e. a Satake-Tits diagram of type A2xA2 but I do not want to have just \dynkin A2 \dynkin A2 but have the nodes paired up.
\end{document}
I am using the excellent package Dynkin-diagram .sty and drawing the diagrams for the non-split version of the Freudenthal-Tits magic square. I managed to draw all but one of them. In picture below the bottom one can easily be drawn with
\dynkin[fold] A{*****}
My question is how do I draw the top one? Thanks a lot
Addition: Benjamin Kindly offered to include FTMS non-split into his package. The others I managed to draw, here the output as well as latex code which produces it
\documentclass[12pt]{amsbook}
\usepackage[dvipsnames,table]{xcolor}
\usepackage{dynkin-diagrams}
\begin{document}
\begin{center}
\Large
\begin{tabular}{| c | c | c | c | c |}\hline
\cellcolor{lightgray!90} $\mathbb{A}\setminus \mathbb{B}$ & \cellcolor{lightgray!90} $\mathbb{K}$ & \cellcolor{lightgray!90} $\mathbb{L}$ & \cellcolor{lightgray!90} $\mathbb{H}$ & \cellcolor{lightgray!90} $\mathbb{O}$ \\ \hline
\cellcolor{lightgray!90} $\mathbb{K}$ & \cellcolor{BurntOrange!80} \dynkin A1 & \cellcolor{BurntOrange!80} \dynkin A{*o} & \cellcolor{BurntOrange!80} \dynkin C{o*o} & \cellcolor{BurntOrange!80} \dynkin F{*ooo} \\ \hline
\cellcolor{lightgray!90} $\mathbb{L}$ & \cellcolor{SeaGreen} \dynkin A{**} & \cellcolor{SeaGreen} \begin{dynkinDiagram}[name=upper]A2
\node (current) at ($(upper root 1)+(0,-.35cm)$) {};
\dynkin[at=(current),name=lower]A2
\begin{pgfonlayer}{Dynkin behind}
\foreach \i in {1,2}{%
\draw[/Dynkin diagram/fold style] ($(upper root \i)$) -- ($(lower root \i)$);}
\end{pgfonlayer}
\end{dynkinDiagram}& \cellcolor{SeaGreen} \dynkin A{*ooo*} & \cellcolor{SeaGreen} \dynkin E{*oooo*}\\ \hline
\cellcolor{lightgray!90} $\mathbb{H}$ & \cellcolor{RoyalBlue!50} \dynkin C{***} & \cellcolor{RoyalBlue!50} \dynkin[fold] A{*****} & \cellcolor{RoyalBlue!50} \dynkin D{*oo*o*} & \cellcolor{RoyalBlue!50} \dynkin E{*oooo**}\\ \hline
\cellcolor{lightgray!90} $\mathbb{O}$ & \cellcolor{OrangeRed!70} \dynkin F{****} & \cellcolor{OrangeRed!70} \begin{dynkinDiagram}[mark=o]E{II} \dynkinRootMark{*}1
\dynkinRootMark{*}3 \dynkinRootMark{*}5 \dynkinRootMark{*}6 \dynkinRootMark{*}2 \dynkinRootMark{*}4 \end{dynkinDiagram}
& \cellcolor{OrangeRed!70} \dynkin[backwards] E{*o**oo*o} & \cellcolor{Red} ${\color{white} \dynkin E{*oooo***}}$\\ \hline
\end{tabular}
\end{center}
\end{document}
Also here are the diagrams as made in Keynote, they are drawn to emphasize the residual property, namely taking a point residue (covering a dot if you are unfamiliar with buildings language) in a picture yields the one above when going from row 4 to 3, row 3 to 2 (row 2 to 1 is different and uses folding)
\documentclass
, includes all relevant\usepackage
commands, ends with\end{document}
and compiles without errors, even if it does not produce your desired output.