I was wondering how i would replicate something like this, having a lot of trouble trying to this using multilineenter image description here

This is where i'm at so far

E_{\pm} = \pm t_{1} 
\sqrt{ 3 + 2\cos {\frac {\sqrt{3} k_{x} a }{2}+\frac{k_{y} a}{2} } \\
+2 \cos{ \frac{ \sqrt{3}k_{x}a}{2}-\frac{k_{y}a}{2}}+2\cos{k_{y} a}}.

2 Answers 2


You can use aligned.

A few points:

  1. I used \; to further separate the coefficient from the square root (but probably I'd use \frac{E_{\pm}}{\pm t_1} to make things clearer)

  2. Inside aligned I used \tfrac to reduce the visual clutter.

  3. \cos doesn't take an argument; less braces in the source.

  4. You forgot a few parentheses.




E_{\pm} = \pm t_{1} \; \sqrt{
  3 & + 2\cos \Bigl(\tfrac {\sqrt{3} k_{x} a }{2}+\tfrac{k_{y} a}{2}\Bigr) \\
    & +2 \cos \Bigl(\tfrac{ \sqrt{3}k_{x}a}{2}-\tfrac{k_{y}a}{2}\Bigr) + 2\cos(k_{y}a)
\hspace{1000pt minus 1fill}


The \hspace tricks are because otherwise the equation number would be moved down. Try without them first: the need may arise depending on your column width.

enter image description here



  E_{\pm} = \pm t_{1} 
      3 + 2\cos {\frac {\sqrt{3} k_{x} a }{2}+\frac{k_{y} a}{2} } \\
      {} +2 \cos{ \frac{ \sqrt{3}k_{x}a}{2}-\frac{k_{y}a}{2}}+2\cos{k_{y}


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