I wanted it to look like \rightlefttarrows (as in one arrow in top of the other)
\begin{tikzcd}
X \ar{r} & \ar[l] B
\end{tikzcd}
The above code does not have that effect and instead fuses both arrows.
asked Dec 19, 2021 at 17:13
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Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking.– Community BotDec 19, 2021 at 17:15
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@Community What is not clear about my question? I want an arrow to be on the top of the other, as in the \rightleftarrows symbol, and the code i provided does not do that.– Carla only proves trivial propDec 19, 2021 at 17:20
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1 Answer
This can be done using the shift left key (or shift right in the second example). Both produce the same output:
The direction of the shift is from the perspective of "walking along the arrow". So if the arrow is drawn from B to X, the left side is below. But if the arrow is drawn from X to B, then left is above, even if the arrow is pointing "backwards". You can adjust the spacing between the arrows to your liking.
\documentclass{article}
\usepackage{tikz-cd}
\begin{document}
\begin{tikzcd}
X \arrow[r, shift left=2pt] & B \arrow[l, shift left=2pt]
\end{tikzcd}
\begin{tikzcd}
X \arrow[r, shift left=2pt] \arrow[r, <-, shift right=2pt]& B
\end{tikzcd}
\end{document}