I am trying to plot the curve shown in the following picture below.enter image description here

Is there a someone who can help me to draw the picture using TikZ or PSTricks.

  • 1
    You will need to give some more informations about what you're struggling with. It's a pretty straightforward drawing, bur unfortunately, without knowing exactly what it is supposed to picture, it's hard to help. What have you already tried?
    – SebGlav
    Jan 5 at 16:31
  • 1
    The TikZ manual (see CTAN, or texdoc.org/serve/tikz/0) starts off with some tutorials, if you study chapter 2 of the manual that will help you drawing something like that. Jan 5 at 16:35
  • 1
    I would recommend you use tikz. To draw a blue line, with an arrow between coordiantes (a,b) and (c,d) you can use \begin{tikzpicture} \draw [blue, ->] (a,b) -- (c,d); \end{tikzpicture}. If you don't want the arrow, don't specify -> in the options. To complete your picture just add more \draw commands with the appropriate coordinates. Hopefully, this is enough to get you started. If you get stuck with a specfic problem, please post a question and include a MWE showing what you have tried so far or how far you got with your drawing. Jan 5 at 17:19

1 Answer 1


If you know the functions of your plots your best option would be pgfplots:




    axis lines=middle,
    xlabel=$\uptau 1$,
    every axis x label/.style={at={(current axis.right of origin)},anchor=west},
    ylabel=$\uptau 2$,
    every axis y label/.style={at={(current axis.above origin)},anchor=south},
    yticklabels={,,}, % removes ticklabels from y axis
    ytick style={draw=none}, % removes ticks from y axis
    xticklabels={,,}, % removes ticklabels from y axis
    xtick style={draw=none} % removes ticks from y axis
        \addplot+[orange,no marks,domain=-1:10,samples=100, thick] {(-x/2)+1} node[midway,yshift=0.5cm] {$f1 (\uptau 1)$};
        \addplot+[blue,no marks,domain=-1:10,samples=100, thick] {(-x/2)-10} node[midway,yshift=0.5cm] {$f2 (\uptau 2)$};     



enter image description here

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.