3

Using the enumitem package, I'd like to get list formatting that looks like this: enter image description here That is, I want top-level enumeration items as well as top-level text to be at the left margin along with the top-level enumeration label, and no newline if the item starts with a second-level enumeration. The closest I've managed to come is this:

\setlist[enumerate]{left=0pt .. \parindent}
\setlist[enumerate,1]{label={\bfseries{\arabic{section}.\arabic{enumi}.}}}
\setlist[enumerate,2]{label=(\alph{enumii})}
\setlist[enumerate,3]{label=(\roman{enumiii})}

which still sets the text of the item to the right of the label. Is there an easy way to do this?

1 Answer 1

3

enumitem's wide=0pt is what you're looking for here, together with a second-level enumerate set to align=left:

enter image description here

\documentclass{article}

\usepackage{enumitem,amsmath}

\setlist[enumerate,1]{label={\bfseries\arabic{section}.\arabic*.},wide=0pt}
\setlist[enumerate,2]{label=(\alph*),align=left}
\setlist[enumerate,3]{label=(\roman*)}

\begin{document}

\section{A section}

\begin{enumerate}
  \item
  \begin{enumerate}
    \item
    We compute as follows:
    \begin{align*}
      (xz \pm nyw)^2 + n (xw \mp yz)^2 &= x^2 z^2 \pm 2 nxyzw + n^2 y^2 w^2 + n x^2 w^2 \mp 2 nxwyz + n y^2 z^2 \\
                                       &= x^2 z^2 + n^2 y^2 w^2 + n x^2 w^2 + n y^2 z^2                         \\
           (x^2 + n y^2) (z^2 + n w^2) &= x^2 z^2 + n x^2 w^2 + n y^2 z^2 + n^2 y^2 w^2
    \end{align*}
    Hence, the right-hand sides are equal, proving (1.6).
    
    \item
    $(a x^2 + c y^2) (a z^2 + c w^2) = (axz \pm cyw)^2 + ac (xw \mp yz)^2$.
  \end{enumerate}
  
  \item This exercise forms part of an \verb|enumerate| and wraps around to the second line of text.
  \begin{enumerate}
    \item
    Item~1
    
    \item
    Item~2
    \begin{enumerate}
      \item
      What is the indentation?
    \end{enumerate}
  \end{enumerate}
\end{enumerate}

\end{document}
1
  • This is great, thanks. I'll wait a bit before accepting it, but it worked as required.
    – rogerl
    Feb 2 at 17:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.