# How to list items in a bullet list format in a table

I want to do something like th

\documentclass{article}
\newcommand{\sbt}{\,\begin{picture}(-1,1)(-1,-3)\circle*{4}\end{picture}\ }
\begin{document}

\begin{itemize}
\item Item 1\hspace{10pt}$\sbt$\hspace{6pt}Item 2 \hspace{10pt}$\sbt$\hspace{6pt}Item 3
\item Item 1\hspace{10pt}$\sbt$\hspace{6pt}Item 2 \hspace{10pt}$\sbt$\hspace{6pt}Item 3
\item Item 1\hspace{10pt}$\sbt$\hspace{6pt}Item 2 \hspace{10pt}$\sbt$\hspace{6pt}Item 3
\end{itemize}
\end{document}

How do I go about doing it?

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• Sep 22 at 19:42
• Thank you, I'l try that out. Sep 22 at 19:44
• There is \textbullet in case you don't know. Sep 22 at 20:25
• textbullet was a bit too big, so I used sbt. Sep 23 at 9:44

(1) Define two commands: one to produce the normal bullets (\sbt} and one for the larger bullets (\sbtx).

(2) Define a 3-column tabular and fill in the rows.

(3) Inject the code to be applied to each row (you need the array package) using eg >{\sbtx\arraybackslash} before the column specification.

\documentclass{article}

\newcommand{\sbt}{\textbullet~~} % normal bullet

\newcommand{\sbtx}{\hspace{10pt}\begin{picture}(-1,1)(-1,-3)\circle*{4}\end{picture}~~~}% large bullet

\begin{document}

\begin{tabular}{>{\sbt}l >{\sbtx}l  >{\sbtx\arraybackslash}l}
Item 1 &  Item 2 & Item 3 \\
Item 1 & Item 2  & Item 3\\
Item 1 & Item 2  & Item 3
\end{tabular}

\end{document}

You can simplify the code by defining a new column type and use it for the last two columns:

\newcolumntype{B}{>{\sbtx\arraybackslash}l} % in the preamble

and

\begin{tabular}{>{\sbt}l B  B }

See here the explanation and use of arraybackslash