10

I am trying to draw this diagram. I do not know how to draw the switch.

enter image description here

I tried

\documentclass[]{article}
\usepackage{circuitikz}
\ctikzset{european resistors}% preferred way to set global options, circuitkz has too many package options...
\usepackage[locale = DE]{siunitx}
\begin{document}
\begin{circuitikz}
\draw (0,0) to[R=$ R $] (2,0) to[R=$ R $] (4,0)  (6,0) to[L,  inductors/width=1.4,inductors/coils=12,l={$L$}] (6,-3) 
    (4,0)  to[capacitor,l={$C$}] (4,-3) 
    (2,0)  to[R=$ R $] (2,-3) 
    (0,0) to[battery2] (0,-3) 
    (0,-3) -- (6,-3);
\end{circuitikz}
\end{document}

And get

enter image description here

2 Answers 2

11

This is a bit tricky, because you need a rotated switch; if I had to draw it from scratch, I would start with the switch and then do the rest by moving relative to it.

I commented on the code --- if you need to look at the perpendicular coordinate system, you can look in the circuitikz manual --- they're explained in the tutorials; or in the TikZ manual itself.

\documentclass[]{article}
\usepackage{circuitikz}
\ctikzset{european resistors}
\usepackage[locale = DE]{siunitx}
\begin{document}
\begin{circuitikz}
\draw (0,0) to[R=$ R $] (2,0) to[R=$ R $] (4,0);
% I would not do it like that --- using relative coordinate is
% better. But...
% Let's place the "node" element (pag 137)
\draw (4.5,0) node[cute spdt mid, anchor=east, rotate=90](SW){};
% connect using the sub-nodes (not needed if you fill the poles, but...)
\draw (4,0) -- (SW-out 1.n) (SW-out 2.s) -- (6,0);
% labels
\path (SW.east) node[above]{$K$} (SW-out 1) node[below]{\strut $a$} (SW-out 2) node[below]{\strut $b$};
% position the capacitor, using perpendicular coordinates
% you need a bit more gimmick if you need it lined with the center of the R
\draw (SW.in) to [C=$C$] (SW.in |- 0,-3);
\draw (6,0) to[L,  inductors/width=1.4,inductors/coils=12,l={$L$}] (6,-3)
    (2,0)  to[R=$ R $] (2,-3)
    (0,0) to[battery2] (0,-3)
    (0,-3) -- (6,-3);
\end{circuitikz}
\end{document}

enter image description here

This also show why the geographical anchors of the switch are positioned lined up with the center of the poles, and why it is needed to provide a way to access the node's sub-poles.

2
  • Can you add a code in your manual to draw a switch. E.x \draw (0,0) to[switch] (2,0)? Sep 24 at 1:26
  • 1
    For a two-pole switch, you can already. The three pole ones and the multiple don't really fit as a path component - they're more like a transistor, don't you think?
    – Rmano
    Sep 24 at 6:50
11

Quite similar to @Rmano answer (+1):

\documentclass[]{article}
\usepackage{circuitikz}
\usepackage[locale = DE]{siunitx}

\begin{document}
\begin{circuitikz} 
\ctikzset{bipoles/capacitor/width/.initial=.1,
          inductors/coils=5, inductors/width=0.8,
          european resistors}
\draw   (0,0) node[spdt, rotate=90] (s) {}
        (s.in)      to [C=$C$]      ++ (0,-2) coordinate (a)
        (s.out 1)   to [R=$R$]      ++ (-2,0) coordinate (b)
                    to [R=$R$]      ++ (-2,0) coordinate (c)
                    to [battery2]   (c |- a)
                    to [short, -*]  (b |- a) 
                    to [short, -*]      (a)  
                    -- ++ (2,0)               coordinate (d)
                    to [L, a=$L$]   (d |- s.in)
                    |- (s.out 2)
        (b)         to [short, *-]  (b |- s.in)
                    to [R=$R$]      (b |- a)       
        ;
\end{circuitikz}
\end{document}

enter image description here

1
  • Yes, quite elegant! I like the lining up of the rlc tank, +1
    – Rmano
    Sep 23 at 22:02

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